An object moves in the eastward direction at constant speed. A net force directed northward acts on the object for 5.0 s. At the
2 answers:
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Answer:
Explanation:
We know the total diameter of the cell (assumed spherical) is:
Then its total radius
On the other hand, we know the thickness of the cell wall is and its density is the same as water (
).
Since density is the relation between the mass and the volume
:
The mass is: (1)
Now if we are talking about this cell as a thin spherical shell, its volume will be:
(2)
Where
Then:
(3)
(4)
Substituting (4) in (1):
(5)
(6)
Knowing and
:
Answer:
the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm
Explanation:
Given the data in the question;
wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m
Index of refraction; n = 1.35
Now, the thinnest thickness of the soap film can be determined from the following expression;
= ( λ / 4n )
so we simply substitute in our given values;
= ( 463 × 10⁻⁹ m ) / 4(1.35)
= ( 463 × 10⁻⁹ m ) / 5.4
= ( 463 × 10⁻⁹ m ) / 4(1.35)
= 8.574 × 10⁻⁸ m
= 85.74 × 10⁻⁹ m
= 85.74 nm
Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm