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Katyanochek1 [597]
4 years ago
10

An object moves in the eastward direction at constant speed. A net force directed northward acts on the object for 5.0 s. At the

end of the 5.0-second period, the net force drops to zero newtons. Which one of the following statements is necessarily true?A. The direction of the object's acceleration depends on how fast the object was initially moving.B. The magnitude of the object's acceleration depends on how fast the object was initially moving.C. The object will be moving eastward when the force drops to zero newtons.D. The final velocity of the object will be directed north of east.E. The change in the velocity of the object will be directed north of west.
Physics
2 answers:
Pie4 years ago
8 0

Answer: D

The final velocity of the object will be directed north of east

Explanation:

lana [24]4 years ago
5 0

Answer:

d

Explanation:

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UkoKoshka [18]

The ratio of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet is 0.78 %.

<h3>Final velocity of the block/bullet system</h3>

Apply the principle of conservation of energy to determine the final velocity of the block/bullet system.

K.E = P.E

¹/₂mv² = mgh

¹/₂v² = gh

v² = 2gh

v = √2gh

where;

  • h is the maximum height reached by the system
  • v is the initial velocity of the system

v = √(2 x 9.8 x 1.1)

v = 4.64 m/s

<h3>Initial velocity of the bullet</h3>

Apply the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

  • u₁ is the initial velocity of the bullet
  • u₂ is the initial velocity of the block
  • v is the final velocity after collision
  • m₁ is mass bullet
  • m₂ is mass of block

(0.0075)u₁ + (0.95)(0) = 4.64(0.0075 + 0.95)

0.0075u₁ = 4.4428

u₁ = 4.4428/0.0075

u₁ = 592.37 m/s

<h3>Initial kinetic energy of the bullet</h3>

K.Ei = ¹/₂m₁u₁²

K.Ei = ¹/₂(0.0075)(592.37)²

K.Ei = 1,315.88 J

<h3>Final kinetic energy of the block/bullet system</h3>

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(0.0075 + 0.95)(4.64)²

K.Ef = 10.31 J

<h3>Ratio of final kinetic energy to initial kinetic energy</h3>

= K.Ef/K.Ei x 100%

= (10.31 / 1,315.88) x 100%

= 0.78 %

Learn more about kinetic energy here: brainly.com/question/25959744

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4 0
2 years ago
while performing a sonogram, to minimize risk to the fetus, which imaging mode trade off would be most appiclable.
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Answer: Use M-mode instead of pulse-wave Doppler to measure the fetal heart rate.

Explanation: M-mode is a famous ultrasound process during the early days of Ultrasound technologies, M-mode has a very high sampling rate. One of the major disadvantages is that it may be difficult to align the M-mode to be the perpendicular to the SEPTUM. M-mode has only one (1) dimensional view of an object,to minimize the risk to the Fetus, M-mode is the most applicable tradeoff. Specifically, M-mode is mainly used because of its Axial and temporal resolution of the structure of objects.

7 0
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-<br> ZOOLS<br> 6) The mass of a motorcycle is 250 kg. What is?<br> A) Its weight on Earth in Newtons?<br> B) Its weight on the
marishachu [46]

Answer:

Explanation:

Weight is actually a force. A force can change depending on its location. A mass remains constant no matter where it is.

A)

F = m * a

m = 250 kg

a = 9.81 m/s^2

F = 250 * 9.81 = 2452.5 N

B)

The acceleration due to gravity on the moon is roughly 1/6 what it is on earth. You can check its value in your notes.

a = 9.81 + (1/6) = 1.635

m = 250

F = 250 * 1.635

F = 408.75

C)

The mass is the same anywhere in the universe.

250 kg

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Answer:

D :)

Explanation:

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