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3 years ago

In an experiment researchers want to determine if the _ Variable causes change in _ variable

Physics

2 answers:

alina1380 [7]3 years ago

6 0

The answer is c) independent, dependent

OleMash [197]3 years ago

6 0

Answer: c). independent, dependent

Explanation:

An independent variable can be define as the variable which can be changed in an experiment. It can be manipulated manually. The effect of such alteration and manipulation can be observed on the dependent variable.

The dependent variable is the one which changes due to the changes and alteration done by the experimenter on the independent variable.

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Ponds and lakes are part of marine ecosystem.<br> True or false ?

finlep [7]

Answer:

True

Explanation:

because they can hold marine organism inside

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3 years ago

Read 2 more answers

The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-1

telo118 [61]

<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>

Explanation:

The half-life $h$ of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this case, we are given the half life of two elements:

beryllium-13: $h_{B-13}=5(10)^{-10}s=0.0000000005s$

beryllium-15: $h_{B-15}=2(10)^{-7}s=0.0000002s$

As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?

We can find it out by the following expression:

$h_{B-15}=X.h_{B-13}$

Where $X$ is the amount we want to find:

$X=\frac{h_{B-15}}{h_{B-13}}$

$X=\frac{2(10)^{-7}s}{5(10)^{-10}s}$

Finally:

$X=400$

Therefore:

The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.

8 0

3 years ago

Calculate the current through a 3.0 Ď‰ resistor with a voltage of 9.0 v across it.

gulaghasi [49]

Answer: 3 A

Explanation:

According to<u> Ohm's law</u>:

$V=R.I$

Where:

$V=9 V$ is the voltage

$R=3\Omega$ is the resistance of the resistor

$I$ is the electric current (the value we want to find)

Isolating $I$ :

$I=\frac{V}{R}$

$I=\frac{9 V}{3\Omega}$

Finally:

$I=3 A$

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3 years ago

A girl lifts a 160-N load to a height of 1 m in 0.5 s. How much power is used to lift the load?

12345 [234]

First, find the work done. W = f*d, so 160 N * 1 m = 160 J. Then divide the work by the time to get the power. P = W/t. P = 160 J / 0.5 s = 320 W.
The answer is 320 W. Hope this helps, and have a great day! :)

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3 years ago

Which is harder, air tight or water tight seals?

Vladimir [108]

Should be an air tight seal

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3 years ago

In an experiment researchers want to determine if the _____ Variable causes change in _____ variable

In an experiment researchers want to determine if the _ Variable causes change in _ variable