I believe flowing water changes the land because eventually frozen water has to melt to flowing water, right?
Answer:
The methane gives Neptune the same blue color as Uranus.
Explanation:
Answer:
5000 Pa
Explanation:
First collect the data you've been given already and make sure to convert into the right units;
<em>Density</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>g</em><em>/</em><em>cm³</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>Kg</em><em>/</em><em> </em><em>m³</em>
<em>acceleration</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>gravity</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>m</em><em>/</em><em>s²</em>
<em>Height</em><em> </em><em>=</em><em> </em><em>5</em><em>0</em><em> </em><em>cm</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>0</em><em>.</em><em>5</em><em> </em><em>m</em>
after collecting the data, use the formula to solve
<em>pressure</em><em> </em><em>=</em><em> </em><em>pgh</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>×</em><em> </em><em>0</em><em>.</em><em>5</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>5</em><em>0</em><em>0</em><em>0</em><em> </em><em>Pa</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
Answer:
9 N
Explanation:
The centripetal force F is F = mrω^2 = (mv^2)/r where m is mass, r is radius of the curve, ω is angular velocity and v is tangential velocity.
In this case, m = 0.5kg, r = 0.5m, v = 3m/s
So F = [0.5kg(3m/s)^2]/0.5m = 9kg-m/s^2 which is 9N
Answer:
Efriction = 768.23 [kJ]
Explanation:
In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.
We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.
The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.
where:
m = mass = 56 [kg]
h = elevation = 1400 [m]
v = velocity = 5.6 [m/s]
![(56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]](https://tex.z-dn.net/?f=%2856%2A9.81%2A1400%29-E_%7Bfriction%7D%3D%5Cfrac%7B1%7D%7B2%7D%2A56%2A%285.6%29%5E%7B2%7D%5C%5C769104%20-E_%7Bfriction%7D%3D%20878.08%20%5C%5CE_%7Bfriction%7D%3D769104-878.08%5C%5CE_%7Bfriction%7D%3D768226%5BJ%5D%20%3D%20768.23%20%5BkJ%5D)
