Answer:
Final speed of the bullet is 228.3 m/s
Explanation:
As we know that there is no external force on the system of wooden block and the bullet
so we can say momentum of the system is conserved here
so here we can say



so we will have


I think the answer is potential
Answer:
Explanation:
Answer is in the attachment below:
As the engine heats up, a natural circulation starts, as coolant rises through the engine block by convection. It passes through the top hose, and into the radiator. Inside the radiator, heat is removed from the coolant as it falls from the top to the bottom.
Hope this helps!