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LekaFEV [45]
3 years ago
13

Mg(s) + HCl (l) --> H2 (g) +MgCl2 (s) A student conducted an experiment with 2g of magnesium and 3 mL of 6M hydrochloric acid

. Equal volumes (3mL) of hydrochloric acid and magnesium strips (2g) were put into each tube. What are the reactants in this reaction?
Chemistry
1 answer:
alexira [117]3 years ago
7 0

Answer: Do you have an image so I can solve it?

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Is strontium phosphide a ionic or covalent bond
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Explanation:

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How many moles of calcium chloride are contained in a 333 gram sample?
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Answer & Explanation:

The molar mass of calcium chloride is 110.98 g/mol. We can use this information to solve this problem. We can set up our equation like this..

\frac{333 g(CaCl2)}{} *\frac{1mol(CaCl2)}{110.98g(CaCl2)}

Multiply straight across on the top and straight across on the bottom.

\frac{333}{110.98}

Now divide.

\frac{333}{110.98}=3.00

So, there are 3.00 moles of calcium chloride contained in a 33 gram sample which is answer choice D.

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A.) During an experiment, a student adds 2.90 g of CaO to 400.0 mL of 1.500 M HCl. The student observes a temperature increase o
Nostrana [21]

Answer:

a.  1.00 x 10⁴ J = 10.0 kJ

b.  1.42 x 10⁴ J = 14.2 kJ

Explanation:

Given the change in temperature during the reaction and assuming the volume of water and density  remains constant, the change in enthalpy for the reaction will be given by

ΔHxn = Q = mCΔT  where,

                               m= mass of water

                               C= specific heat of water, and

                               ΔT= change in temperature

a. mH₂O = 400.0 mL x 1.00g/mL = 400.00 g

Q = ΔHrxn = 400.00g x 4.184 J/gºC x 6.00 ºC = 1.00 x 10⁴ J = 10.0 kJ

b. mH₂O = 200.0 mL x 1.00 g/mL = 200.0 g

Q = ΔHrxn = 200.00 g x 4.184 J/gºC x 17.0ºC =  1.42 x 10⁴ J = 14.2 kJ

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