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MrRa [10]
3 years ago
11

A pebble is dropped into a cup of water and sinks to the bottom ofthe cup. A solid metal bead of exactly the same size is droppe

d into the same cup and sinks to the bottom of the cup. How do the pebble and the metal bead compare?
Chemistry
2 answers:
enot [183]3 years ago
4 0

Answer:

Both the pebble and metal bead of the same mass will be equally accelerated  if they are at the same place, in this case, they are in the same place meaning they will be accelerated at the same speed towards the earth. Thus even if they are in the water they will sink at the same speed and finally will reach the bottom of the cup.

jonny [76]3 years ago
3 0

Answer:

A solid metal bead of the same size is dropped into the same cup and sinks to the bottom of the cup. How do the pebble and the metal bead compare? They both have the same mass. They are both denser than water.

Explanation:

nun

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What happens when you drop iodine on a leaf?
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hope that helps :)
6 0
3 years ago
For which of the following reactions does Kc = Kp?
Julli [10]
None of the choices are right
4 0
3 years ago
What is the name of CH3CH2OCH2CH3?
natali 33 [55]

Answer:

It is an ether so the nomenclature rule for naming the above compound will be:Alkoxy alkane , generally Alkoxy represent the smaller alkyl group and as in the above question both the alkyl group are same so it's IUPAC Name will be: Ethoxy ethane or Diethylether both are correct

Explanation:

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5 0
3 years ago
What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.
Rzqust [24]

Molar solubility of AgCl will be  0.59 ×  10^{-10} M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

K_{sp} = 1.77 × 10^{-10}

The reaction can be written as:

AgCl ⇔ Ag^{+} + Cl^{-}

s            s         (s+0.30)

K_{sp}  = [Ag^{+} ]+ [Cl^{-}]

1.77 × 10^{-10} = s (0.30)

s = 1.77 × 10^{-10}  / 0.3

s = 0.59 ×  10^{-10} M

Therefore, molar solubility of AgCl will be  0.59 ×  10^{-10} M.

To know more about molar solubility

brainly.com/question/16243859

#SPJ4

3 0
1 year ago
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