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RoseWind [281]
3 years ago
5

Corals absorb ______ from the ocean to form their skeletons.

Chemistry
2 answers:
Nina [5.8K]3 years ago
3 0
<span>They absorb calcium ions and bicarbonate (hydrogen carbonate) ions.
Sooo B
I hope this helps! :)
</span>
saul85 [17]3 years ago
3 0

Answer: The correct option is b. Calcium

Explanation: Ocean water consists of a large amount of Chloride (Cl^-), Sulfate (SO_4^{2-}), Magnesium (Mg^{2+}), Sodium (Na^+), Calcium (Ca^{2+}) and Potassium (K^+) ions.

The coral animals absorb calcium element from the ocean to form their skeleton. Then, the calcium ions combine with carbon and oxygen to form calcite.

Hence, the correct option is b.

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The electron configuration of an element is shown below.
gayaneshka [121]

Answer:it is in group 7

Explanation:it is in this group because in the increasing number of atomic number the element is found in group seven. The element is likely to receive 3 electrons while bonding with another element to make it stable.

5 0
2 years ago
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Molecules tend to move from areas of ____ concentration to areas of _____ concentration.
masha68 [24]
Areas of high concentration to areas of low concentration.
5 0
3 years ago
Which substance is most likely to heat up the fastest?
ddd [48]
The best substance to heat up the fastest would be blue fire
7 0
3 years ago
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How many moles are in 109 grams of kf
lions [1.4K]

Answer:

Explanation:

Molar mass of KF= 39 + 19= 58g/mol

Mass of KF = 109g

Amount = mass/molar mass

Amount = 109/58

Amount = 1.9moles

4 0
3 years ago
If 0.255 moles of AgNO₃ react with 0.155 moles of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ co
Ber [7]

Answer: 6.162g of Ag2SO4 could be formed

Explanation:

Given;

0.255 moles of AgNO3

0.155 moles of H2SO4

Balanced equation will be given as;

2AgNO3(aq) + H2SO4(aq) -> Ag2SO4(s) + 2HNO3(aq)

Seeing that 2 moles of AgNO3 is required to react with 1 moles of H2SO4 to produce 1 mole of Ag2SO4,

Therefore the number of moles of Ag2SO4 produced is given by,

n(Ag2SO4) = 0.255 mol of AgNO3 ×

[0.155mol H2SO4 ÷ 2 mol AgNO3] x

[ 1 mol Ag2SO4 ÷ 1 mol H2SO4]

= 0.0198 mol of Ag2SO4.

mass = no of moles x molar mass

From literature, molar mass of Ag2SO4 = 311.799g/mol.

Thus,

Mass = 0.0198 x 311.799

= 6.162g

Therefore, 6.162g of Ag2SO4 could be formed

4 0
3 years ago
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