The answer would be 20% (B)
Answer:
450.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂).</em>
<em></em>
V₁ = 760.0 L, P₁ = 450.0 mm Hg,
V₂ = ??? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).
∴ V₂ = (P₁V₁)/(P₂) = (760.0 L)(450.0 mm Hg)/(760.0 mm Hg) = 450.0 L.
Answer:
20.5 torr
Explanation:
Given parameters:
Volume of tank = 15L
Pressure of tank = 8.2 x 10⁴torr
Volume of empty chamber = 6.0 x 10⁴L
Unknown:
New pressure of the gas in this chamber = ?
Solution:
To solve this problem, a good knowledge of the gas law will suffice here. Since pressure and volume relationships are under consideration, the Boyle's law is the proper gas law to apply.
Boyle's law states that "at constant temperature, the volume of fixed mass of gas is inversely proportional to the pressure of the gas".
Mathematically;
(Pressure x volume) of tank = (Pressure x volume ) of empty chamber
15 x 8.2 x 10⁴ = Pressure of empty chamber x 6 x 10⁴
Pressure of empty chamber = 20.5 torr
<span>pOH = 9.2
pH = 4.8</span><span>
That's your </span>answer!!
Hope I helped!! :)
B because I’m 100% is currect
