Answer:
When a copper is drawn into wire the only change that occurs is change in its shape and size no change will take place into its composition that is the wires are still possessing the properties of copper metal. Thus, a physical change takes place when copper is drawn into wire.
Steam because steam comes from water which the energy makes it into steam
Li2O is the formula for <span> lithium oxide</span>
Answer:
The new pressure of the pump is 26.05 atm or 2639.4 kPa
Explanation:
Step 1: Data given
Volume of the bicycle tire pump = 252 mL = 0.252 L
Pressure of air = 995 kPa = 9.81989 atm
The volume of the pump is reduced to 95.0 mL = 0.095 L
Step 2: Calculate the new pressure
V1*P1 = V2*P2
⇒with V1 = the initial volume of the bicycle tire pump = 0.252 L
⇒with P1 = the initial pressure of the pump = 9.81989 atm = 995 kPa
⇒with V2 = the reduced volume of the pump = 0.095 L
⇒with P2 = the new pressure = TO BE DETERMINED
0.252 L * 9.81989 atm = 0.095 L * P2
P2 = 26.05 atm
The new pressure is 26.05 atm
OR
0.252 L * 995 = 0.095 L * P2
P2 = 2639.4 kPa
The new pressure of the pump is 26.05 atm or 2639.4 kPa
Answer:
6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature.
Explanation:
2H₂O(g) ⇄ 2H₂(g) + O₂(g)
Partial pressure of H₂O = 0.0500 atm
Partial pressure of H₂ = 0.00150 atm
Partial pressure of O₂ = 0.00150 atm
The expression of Kp for the given chemical equation is:
![K_p = \frac{[H_2]^2[O_2]}{H_2O}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7BH_2O%7D)
6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature
