Answer:
Option B 120
Explanation:
There are three variables,<em> ans, x </em>and <em>y</em> given in the code. In beginning, the variable. <em>ans,</em> holds value of 10. And variable <em>x</em> and <em>y</em> hold value of 65 and 55, respectively. Since the value held by x is bigger than one held by y, the if condition is met and the statement ans = x + y will run. The execution of this statement will total x with y -> 65 + 55 and the initial value of <em>ans is </em>overwritten by the addition result which is 120.
Answer:
Following are the program to this question:
#include <iostream> //defining header file
using namespace std;
int hailstoneLength(int n) //defining method hailstoneLength
{
int t=1; //defining integer variable assign
while(n!=1) //define a loop that checks value is not equal to 1
{
if(n%2==0) // check even number condition
{
n=n/2; // divide the value by 2 and store its remainder value in n
t++; //increment value of t by 1.
}
else
{
n=n*3+1; //calculate and hold value in n
t++; //increment value of t variable by 1
}
}
return t; //return value
}
int main() //defining main method
{
int n; //defining integer variable
cout<<"Enter any number: "; //print message
cin>> n; //input value
cout<<hailstoneLength(n); //call method and print its value
return 0;
}
Output:
Enter any number: 3
8
Explanation:
Program description can be given as follows:
- In the given C++ language program an integer method "hailstoneLength", is declared, that accepts an integer variable "n" in its parameter.
- Inside the method, an integer variable t is declared, that assign a value that is 1, in the next line, a while loop is declared, that uses if block to check even condition if number is even it divide by 2 and increment t variable value by 1.
- If the number is odd it will multiply the value by 3 and add 1 and increment t by 1 then it will go to if block to check value again. when value of n is not equal to 1 it will return t variable value.
- In the main method, an integer variable "n" is used that call the method and print its return value.
Answer:
The answer is "5.5 and 90.90%"
Explanation:
For point 1:
To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (
) and the increased stages ().
Although not enhanced, this would take almost as long () and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as 
. Thus the corresponding total speed without enhancement is 
Its overall speed is:
For point 2:
We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:
Answer:
First blank: producer
Second blank: Hairdressers
