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Nookie1986 [14]
4 years ago
9

The density of ethanol is 0.79 g/mL. The density of acetic acid is 1.05 g/mL. Assuming that each

Chemistry
1 answer:
m_a_m_a [10]4 years ago
7 0
The percent of the product would be 23
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2. The change in internal energy for the expansion of a gas sample is -4750 J. How much work is done if the gas sample loses 112
Radda [10]

Answer:

The work done by the gas expansion is 5875 J,

Since the work done is positive, the work is done by the gas on the surroundings.

Explanation:

Given;

change in internal energy, ΔU = -4750 J

heat transferred to the system, Q = 1125 J

The change in internal energy is given by;

ΔU = Q - W

Where;

W is the work done by the system

The work done by the system is calculated as;

W = Q - ΔU

W =  1125 - (-4750)

W = 1125 + 4750

W = 5875 J

Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).

Therefore, the work done by the gas expansion is 5875 J

7 0
3 years ago
Consider the following reaction of the commercial production of SO3 using sulfur dioxide and oxygen: ​ SO2(g) + O2(g) → SO3(g) ​
kipiarov [429]

Answer:

m_{SO_3}=18.93gSO_3

V_{SO_3}=5.3LSO_3

Explanation:

Hello,

STP conditions are P=1 atm and T=273.15 K, thus, the reacting moles are:

n_{SO_2}=\frac{5.3L*1atm}{0.082\frac{atm*L}{mol*K}*273.15K}=0.2366molSO_2\\n_{O_2}=\frac{4.7L*1atm}{0.082\frac{atm*L}{mol*K}*273.15K}=0.2098molO_2

Now, the balanced chemical reaction turns out into:

2SO_2(g) + O_2(g) --> 2SO_3(g)

Thus, the exact moles of oxygen that completely react with 0.2366 moles of sulfur dioxide are (limiting reagent identification):

0.2366molSO_2*\frac{1molO_2}{2molSO_2}=0.1182molO_2

Since 0.2098 moles of oxygen are available, we stipulate the oxygen is in excess and the sulfur dioxide is the limiting reagent. In such a way, the yielded grams of sulfur trioxide turn out into:

m_{SO_3}=0.2366molSO_2*\frac{2molSO_3}{2molSO_2}*\frac{80gSO_3}{1molSO_3} \\m_{SO_3}=18.93gSO_3

By using the ideal gas equation, one computes the volume as:

V_{SO_3}=\frac{mRT}{MP}=\frac{18.93g*0.082\frac{atm*L}{mol*K} *273.15K}{80g/mol*1atm}\\V_{SO_3}=5.3LSO_3

It has sense for volume since the mole ratio is 2/2 between sulfur dioxide and sulfur trioxide.

Best regards.

6 0
3 years ago
If you have a density of 2.5 g/mL and a mass of 5 g, what is the volume?
stich3 [128]

Answer:2 ml.

Explanation:Volume. 2.5 g/ml = 5g/Volume. Volume = 5g/(2.5 g/ml). = 2 ml.

8 0
3 years ago
Which option correctly matches the chemical formula of a compound with its
azamat

Answer:

B. NO₂, nitrogen dioxide

Explanation:

Nitrogen dioxide is one of the oxides of nitrogen. It reacts highly and is very harmful for the health of humans. It is regarded as one of the pollutants of the air pollution. The chemical formula of Nitrogen dioxide is NO₂. This gas is produced during the manufacturing of the fertilizers in the industries. Burning of the fossil fuels also contribute in the emission of nitrogen dioxide. Two atoms of oxygen when reacts with one atom of Nitrogen, Nitrogen dioxide is formed.

6 0
3 years ago
‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎<br>‎‎‎‎‎<br>‎‎‎‎‎<br>‎‎‎‎‎<br>‎‎‎‎‎<br>‎‎‎‎‎
ddd [48]

Answer:

crazy stuff bro

Add on:

5 0
3 years ago
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