False is the correct answer.
The correct answer to this question is A
Answer:
1.02 grams
Explanation:
The reaction between Na₃PO₄ and BaCl₂ is:
2Na₃PO₄(aq) + 3BaCl₂(aq) → Ba₃(PO₄)₂(s) + 6NaCl(aq)
We need to find the number of moles of Na₃PO₄ and BaCl₂:


Now, we need to find the limiting reactant:

We have that it is needed 0.0033 moles of Na₃PO₄ to react with BaCl₂ and we have 0.01 moles of Na₃PO₄, so the limiting reactant is BaCl₂.
The number of moles of Ba₃(PO₄)₂ is:

Finally, the mass of Ba₃(PO₄)₂ is:

Therefore, should be obtained 1.02 grams of the precipitate.
I hope it helps you!
Answer:
CaCO
→ CO
+ CaO
Explanation:
Given reactants:
Omar heated small piece of calcium carbonate
Product;
it gave off carbon dioxide gas and solid calcium oxide;
Problem,
Equation of the reaction;
Solution:
Calcium carbonate → Carbon dioxide + Calcium oxide
CaCO
→ CO
+ CaO