Ask question

Ask question

All categories

1 year ago

5

Two balls are at the same height and released at the same time. One ball is dropped and hits the ground 5s later. The 2nd ball i

s pushed out so it moves horizontally. When does the second ball hit the ground? How far does the 2nd ball travel horizontally?

1 answer:

ASHA 777 [7]1 year ago

5 0

Answer:

The second ball hits at the same time.

Distance travelled is 65 meters

Explanation:

You might be interested in

What is an error in a lab mean?

timurjin [86]

You have done something incorrectly. such as your data.

5 0

3 years ago

An object is moving at a constant velocity of 4 m/s. What is it's initial velocity?

AysviL [449]

Answer:

How does sperm cells get out of the genitals of the male's? What produces the sperms? Why does women have to hope on the genitals?

kjd;oisdnvliusdh;j;ovh;dfkn'grGXC/?jd;.d

sgo]er]'gr'kspdzg'

er

dg

rd

h'

d/h

'dfhdf

t'

Explanation:

4 0

2 years ago

A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load

Alisiya [41]

Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

It is given that,

Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

$m_1v_1=(m_1+m_2)v$

$v=\dfrac{m_1v_1}{m_1+m_2}$

$v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}$

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

6 0

2 years ago

1. A small package is dropped from the Golden Gate Bridge. What is the velocity of the package

Sidana [21]

The velocity of the package after it has fallen for 3.0 s is 29.4 m/s

From the question,

A small package is dropped from the Golden Gate Bridge.

This means the initial velocity of the package is 0 m/s.

We are to calculate the velocity of the package after it has fallen for 3.0 s.

From one of the equations of kinematics for objects falling freely,

We have that,

v = u + gt

Where

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

and t is time

To calculate the velocity of the package after it has fallen for 3.0 s

That means, we will determine the value of v, at time t = 3.0 s

The parameters are

u = 0 m/s

g = 9.8 m/s²

t = 3.0 s

Putting these values into the equation

v = u + gt

We get

v = 0 + (9.8×3.0)

v = 0 + 29.4

v = 29.4 m/s

Hence, the velocity of the package after it has fallen for 3.0 s is 29.4 m/s

Learn more here: brainly.com/question/13327816

6 0

2 years ago

A solenoid of radius r 5 1.25 cm and length , 5 30.0 cm has 300 turns and carries 12.0 A. (a) Calculate the flux through the sur

Elina [12.6K]

Answer:

$\phi = 7.4 \times 10^{-6} Wb$

Explanation:

Magnetic field due to a long solenoid at the center is given by

$B = \frac{\mu_o N i}{L}$

here we know that

N = 300

L = 30 cm

i = 12 A

now magnetic field is given as

$B = \frac{(4\pi \times 10^{-7})(300)(12)}{0.30}$

$B = 0.015 T$

Now magnetic flux through the disc is given as

$\phi = B.A$

$\phi = (0.015)(\pi r^2)$

$\phi = (0.015)(\pi)(0.0125)^2$

$\phi = 7.4 \times 10^{-6} Wb$

8 0

3 years ago