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natima [27]
3 years ago
8

Suppose a 63-kg boy and a 40-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration

of the girl toward the boy is 3.0 m/s2, find the magnitude of the acceleration of the boy toward the girl.
Physics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

a₂ = 1.9 m/s²

Explanation:

Newton's third law or principle of action and reaction :

Force of the boy on the girl = -  Force of the girl on the boy

Fbg = - Fgb  Formula (1)

Newton's second law

∑F = m*a Formula (2)

∑F : algebraic sum of the forces in Newton (N)  

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Newton's second law to the girl

m₁ : girl mass

a₁ : acceleration of the girl toward the boy

∑F = m₁*a₁

Fbg= (40kg)*(3 m/s²)

Fbg = 120 N

Newton's second law to the boy

m₂: boy mass

a₂ : acceleration of the boy toward the girl

∑F = m₂*a₂

Fgb = (63)*a₂

120 = (63)*a₂

a₂ = 120 / (63)

a₂ = 1.9 m/s²

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Answer:

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Given that,

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stress=\alpha Y\Delta T

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Put the value into the formula

12\times10^{6}=17.3\times10^{-6}\times190\times10^{9}\times(T_{2}-15)

(T_{2}-15)=\dfrac{12\times10^{6}}{17.3\times10^{-6}\times190\times10^{9}}

T_{2}=3.650+15

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We need to calculate the temperature of magnesium

Using formula of  stress

stress=\alpha Y\Delta T

Put the value into the formula

12\times10^{6}=25.2\times10^{-6}\times45\times10^{9}\times(T_{2}-15)

(T_{2}-15)=\dfrac{12\times10^{6}}{25.2\times10^{-6}\times45\times10^{9}}

T_{2}=10.5+15

T_{2}=25.58^{\circ}

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Amiraneli [1.4K]

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In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

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t is time measured in seconds.

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