round up given mass to a whole number



Hence our answer is Rhodium-103
Answer:
A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.
Explanation:
Power refers to the amount of work done (or energy consumed) per unit of time. It is usually measured in watts (W), which is equal to 1 Joules per second (
)
So, by definition, to calculate the power consumed or supplied in a time interval the following expression is used:

where P is the power measured in Watts, W is the work measured in Joules, and t is the time measured in seconds.
In this case:
- P=100 Watt
- W= 10,000 J
- t= ?
Replacing:

Solving:

t=100 seconds
<u><em>
A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.</em></u>
<u><em></em></u>
1.180
2.-900
3.20
4.8
Hope this helps
The trend of ionization energy in the periodic table is decreasing from right to left and from top to bottom. In this case, we are given with elements <span>K, Ca, Ge, Se, Br, Kr and see the periodic table to check the trend. The answer from highest to lowest Kr, Br, Se, Ge, Ca, and K</span>
The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O
M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
M(HCl) = 1+ 36.5= 37.5
moles of HCl = 5.5/37.5=0.14
M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)
M(C2H6O)= 2x12+ 6 + 16=46,
moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles
</span>
the sum of the moles is 0.14 + <span>4.35 </span> = 4.501 moles
finally, <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
</span>
because it can be found by 0.14 / 4.501= 0.031