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DaniilM [7]
2 years ago
9

What is the balanced form of the chemical equation shown below? N2(g) + H2(g) → NH3(g) -

Chemistry
1 answer:
Rom4ik [11]2 years ago
6 0
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit

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What is the molality of an aqueous KCl solution with a mole fraction of KCl, XKCl = 0.175? (The molar mass of KCl = 74.55 g/mol
NARA [144]

Answer:

The molality of the KCl solution is 11.8 molal

Explanation:

Step 1: Data given

Mol fracrion KCl = 0.175

Molar mass KCl = 74.55 g/mol

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mol fraction H2O

mol fraction H2O = 1 - 0.175 = 0.825

Step 3: Calulate mass of H2O

Suppose the total moles = 1.0 mol

Mass H2O = moles H2O * molar mass

Mass H2O = 0.825 * 18.02 g/mol

Mass H2O = 14.87 grams = 0.01487 kg

Step 4: Calculate molality

Molality KCl = 0.175 / 0.01487 kg

Molality KCl = 11.8 molal

The molality of the KCl solution is 11.8 molal

5 0
3 years ago
A researcher recorder that a chemical reaction require 2.90 gal water and raised the temperature of the reaction vessel by 57°F.
Ivan

Answer:

10.875L

Explanation:

The problem here is a simple conversion. The conversion is from gal to liters Liter is a SI unit for recording volume as stated in the problem.

Given that:

              1 gallon of water = 3.75L

              2.90 gallon will be 2.9 x 3.75; 10.875L

4 0
3 years ago
In chemical reactions, the number of atoms in the product is ________________.
irina1246 [14]

Answer:

A

Explanation:

7 0
3 years ago
What is the mass of 0.28 mol of iron
maria [59]
Mass = number of mol x molar mass
Mass = 0.28mol x 55.8g/mol
Mass = 15.624g
5 0
3 years ago
Read 2 more answers
A sample of hydrogen occupies a volume of 351 mL at a temperature of 20 degrees Celsius. What is the new volume if the temperatu
xeze [42]
Volume of Hydrogen V1 = 351mL 
Temperature T1 = 20 = 20 + 273 = 293 K 
Temperature T2 = 38 = 38 + 273 = 311 K 
We have V1 x T2 = V2 x T1 
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56 
Volume at 38 C = 373 ml
6 0
3 years ago
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