2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH
In a reaction, the reducing agent is the element or compound that donates electron or the one tht loses electrons. The oxidized species. The opposite is called the oxidizing agent. It is the one who accepts the electrons lost. For this reaction KMnO4 is reduced into MnO2.
Answer:
By adding the solute in to solution boiling point is increased while freezing point is decreased.
Explanation:
When solute in added into the solvent the boiling point of solvent increases for example,
Water is boiled at 100 °C, when sodium chloride is added its boiling point increased. Ions of salt interact with solvent and prevent the water molecules to escape from the surface and form gas molecules. In order to make it boiled solution must be heated above 100 °C.
But there is different case with freezing point. Freezing point is the state in which substance converted into the solid. At given temperature when solute is added into the solvent it prevent the formation of solid. It required time to decrease the temperature first and as the temperature is decreases solid is formed.
Answer:
The correct answer is option b, that is, 2.1 M Na₃PO₄.
Explanation:
The solution with the largest concentration of ions will possess the highest conductivity.
a) 3.0 M NaCl
NaCl ⇔ Na⁺ + Cl⁻
Here the total number of ions is 2, therefore, the concentration of ions is 3.0 × 2 = 6.0 M
b) 2.1 M Na₃PO₄
Na₃PO₄ ⇔ 3 Na⁺ + PO₄³⁻
Here the total number of ions i 4. Therefore, the concentration of ions is
2.1 × 4 = 8.4 M.
c) 2.4 M CaCl₂
CaCl₂ ⇔ Ca²⁺ + 2Cl⁻
The total number of ions is 3. Therefore, the concentration of ions is
2.4 × 3 = 7.2 M
d) 3.2 M NH₄NO₃
NH₄NO₃ ⇔ NH₄⁺ + NO₃⁻
The total number of ions is 2. The concentration of ions will be,
3.2 × 2 = 6.4 M
Hence, the highest conductivity will be of 2.1 M Na₃PO₄.
