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4 years ago

What are the workings of a electromagnet? plssssssssssssssssssssss answer its U.R.G.E.N.T

Physics

1 answer:

Rudiy274 years ago

8 0

Answer:

Wh en an ele ctric c urrent flows in a wire, it cre at es a ma g ne tic fie ld around the wire. Thi s ef fect can be used to make an electromagnet . A simple electr om agnet a length of wire tur ned into a c oil an d co nnected to a batt e ry or po wer sup ply.

Explanation:

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olya-2409 [2.1K]

Answer:

option 1

Explanation:

i just used the SOH CAH TOA, and since the given is tan=opposite/adjacent, that should be the answer

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4 years ago

I need a short answer ?

mars1129 [50]

Answer:

Explanation:

7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s

7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m

h = (45sin14.5)² / (2(9.81)) = 6.47 m

which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.

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3 years ago

Does groundwater flow or stay still?

zhenek [66]

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3 years ago

A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second

Maru [420]

The value of the second charge is 1.2 nC.

<h3>Electric potential</h3>

The work done in moving the charge from infinity to the given position is calculated as follows;

W = Eq₂

E = W/q₂

<h3>Magnitude of second charge</h3>

The magnitude of the second charge is determined by applying Coulomb's law.

$E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC$

Thus, the value of the second charge is 1.2 nC.

Learn more about electric potential here: brainly.com/question/14306881

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2 years ago

A northfield raider defensive back runs 20 m in 2.5 s what’s the average speed

Kaylis [27]

The average speed is 8 miles

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4 years ago