Answer:
Biotic factors are the living component of an environment while abiotic factors are the non living component of an environment.
Biotic factors of Mono lake include plants, animals, fungi, algae and bacteria
Abiotic factors of Mono lake include sunlight, temperature, moisture, wind or water currents, soil type, and nutrient availability.
While the biotic and abiotic factors on Land inhabited by humans including Me are :
Biotic factors-Plants ,animals, bacteria
Abiotic factors-Sunlight, heat/ temperature, Climate, weather, water sources.
Answer:
The change in entropy ΔS = 0.0011 kJ/(kg·K)
Explanation:
The given information are;
The mass of water at 20.0°C = 1.0 kg
The mass of water at 80.0°C = 2.0 kg
The heat content per kg of each of the mass of water is given as follows;
The heat content of the mass of water at 20.0°C = h₁ = 83.92 KJ/kg
The heat content of the mass of water at 80.0°C = h₂ = 334.949 KJ/kg
Therefore, the total heat of the the two bodies = 83.92 + 2*334.949 = 753.818 kJ/kg
The heat energy of the mixture =
1 × 4200 × (T - 20) = 2 × 4200 × (80 - T)
∴ T = 60°C
The heat content, of the water at 60° = 251.154 kJ/kg
Therefore, the heat content of water in the 3 kg of the mixture = 3 × 251.154 = 753.462
The change in entropy ΔS = ΔH/T = (753.818 - 753.462)/(60 + 273.15) = 0.0011 kJ/(kg·K).
We can solve for the resultant x and y components by using
the sine and cosine functions.
resultant x = 2.5 cos 35 + 5.2 cos 22 = 6.87 km
resultant y = 2.5 sin 35 + 5.2 sin 22 = 3.38 km
The resultant displacement is calculated using hypotenuse
equation:
displacement = sqrt (6.87^2 + 3.38^2)
displacement = 7.66 km
The resultant angle is:
θ = tan^-1 (3.38 / 6.87)
θ = 26.20°
Therefore the magnitude and direction is:
7.66 km, 26.20° to the ground
It transforms into heat energy
