part 1
mass = ρ x V
mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg
PE (potential energy)= mgh
PE = 6608.2 kg x 9.81 x 403
PE = 2.61 x 10⁷ J
part 2
megaton of TNT (Mt) =4.2 x 10¹⁵ J
convert PE to Mt:
2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt
Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
![=\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B534%5Ctimes%28%20485g%29%5Ctimes%28%2010%5E3mg%2Fg%29%7D%7B%287.9g%2Fcm%5E3%29%20%5Ctimes%20%28100in%5E2%29%5Ctimes%20%2824h%2Fday%29%5Ctimes%20%28365day%2Fyr%29%5Ctimes%201yr%7D)
=37.4mpy
mm/yr
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
![=\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B87.6%5Ctimes%20%28485g%29%5Ctimes%20%2810%5E3%20mg%2Fg%29%7D%7B%287.9g%2Fcm%5E3%29%5Ctimes%20%28100in%5E2%29%5Ctimes%282.54cm%2Fin%29%5E2%5Ctimes%20%2824h%2Fday%29%5Ctimes%20%28365day%2Fyr%29%5Ctimes%201yr%7D)
=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
When chilies burn in our mouths, the surrounding temperature does not affect how hot the taste of the chilli is. It is only the spiciness that we taste in our mouths. This spiciness is caused by the chemical called capsaicin. This chemical is contained in the cells of the chilli. Capsaicin irritates the cells in your mouth so that is why you feel the discomfort in your mouth.
Hope it helps :)
The formula for acceleration is a = F/m; Where: F = force; m = mass
Given: F = .6n; m = .4kg; a = ?
a = F/m
= .6/.4
= 1.5
Therefore, the acceleration of the plate is 1.5 m/s^2