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Sveta_85 [38]
3 years ago
11

Graph the function y=2x+3

Mathematics
1 answer:
stealth61 [152]3 years ago
3 0
I will show how to do it:

Step 1:  Start your point at 3 in the y axis (line going upwards)

Step 2: Move up twice.

Step 3: Now go to the right once.

Step 4: Use a ruler to draw the line.

Step 5: Cross check by picking two points that are on the line. Or use the formula - y2 - y1 / x2 - x1
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Which of the following conditions must be met in order to make a statistical inference about a population based on a sample
klasskru [66]

Answer:

For this case if we want to conclude that  the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

\bar X \sim (\mu, \frac{\sigma}{\sqrt{n}})

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:

n>= 30

Step-by-step explanation:

For this case if we want to conclude that  the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

\bar X \sim (\mu, \frac{\sigma}{\sqrt{n}})

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:

n>= 30

7 0
3 years ago
___ tens 15 ones = 6 tens 5 ones
Bezzdna [24]
The answer would be 5 tens.
4 0
3 years ago
Read 2 more answers
Someone help me with this answer please !!
Aleks04 [339]

Answer:

-27

Step-by-step explanation:

7 0
3 years ago
A) 5/13<br>B) 5/12<br>C) 12/13<br>D) 12/5​
shutvik [7]

Answer:

the answer would be C.... 12/13

4 0
3 years ago
What is the justification for the first step in proving the formula for factoring the sum of cubes?
Anna11 [10]

Explanation:

The formula isnt correctly written, it should state:

a^3+b^3 = (a+b)(a^2-ab+b^2)

You have to start from (a+b)(a^2-ab+b^2)  and end in a³+b³. On your first step, you need to use the distributive property.

(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)

This is equal to

a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

5 0
4 years ago
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