Answer:
3.40x10¹⁰ grams
Explanation:
First we<u> convert 5.25x10³² atoms to moles</u>, using <em>Avogadro's number</em>:
5.25x10³² atoms ÷ 6.023x10²³ atoms/mol = 88.72x10⁸ mol
Then we<u> convert K moles to grams</u>, using its <em>molar mass</em>:
88.72x10⁸ mol * 39 g/mol = 3.40x10¹⁰ g
So 5.25x10³² atoms of K would weigh 3.40x10¹⁰ grams.
Answer:
9 (1-2x²)
Explanation:
The given expression is:
30 - 9x²*2 - 21 - 4 + 4
The first step is to compute the multiplication. This will give:
30 - 18x² - 21 - 4 + 4
Then, we will add like terms as follows:
(30-21-4+4) - 18x²
= 9 - 18x²
Finally, we can take the 9 as a common factor from both terms, this will give:
9 (1-2x²)
Hope this helps :)
The question is incomplete, the complete question is:
Standard reduction potentials for zinc(II) and copper(II)
The standard reduction potential for a substance indicates how readily that substance gains electrons relative to other substances at standard conditions. The more positive the reduction potential, the more easily the substance gains electrons. Consider the following:
Zn2+(aq)+2e−→Zn(s),Cu2+(aq)+2e−→Cu(s), E∘red=−0.763 V E∘red=+0.337 V
Part B
What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.
Express your answer to three decimal places and include the appropriate units.
Answer:
1.100 V
Explanation:
E∘cell= E∘cathode - E∘anode
E∘cathode= +0.337 V
E∘anode= −0.763 V
E∘cell= 0.337-(-0.763)
E∘cell= 1.1V
Answer:
A and C.
Explanation:
the question clearly states "<em>five</em> crickets in each <em>identical</em> container".
Answer:
V=25.133 cm^3
(Is 4 the diameter you were given? To get one of those answers, I think you May have put the wrong diameter)
Explanation:
Radius is diameter/2
R=4/2
R=2
Volume of a sphere=4/3πr3
V=4/3π(2)3
V=25.133 cm^3
