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3 years ago

find the area of the faded region. Round your answer to the nearest HUNDREDTH. Just put in the answer.

Mathematics

1 answer:

blsea [12.9K]3 years ago

3 0

Answer:

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love u this is irrelevent but idrc lol

Step-by-step explanation:

You might be interested in

The sun shines at a 30° angle to the ground. To the nearest inch, how long is the shadow cast by a 72-in. tall fence post?

tensa zangetsu [6.8K]

The length of the shadow is 124.7 in

<u>Explanation:</u>

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Given:

Angle, θ = 30°

Height of the fence, h = 72 in

Length of the shadow, l = ?

Given:

tan 30° = $\frac{perpendicular}{base} = \frac{height of the fence}{length of the shadow}$

$\frac{1}{\sqrt{3} } = \frac{72}{l} \\\\l = 72\sqrt{3} \\\\l = 124.7 in$

Therefore, the length of the shadow is 124.7 in

5 0

2 years ago

Select all values of x that make the inequality -x + 8 ≥11 true.

mash [69]

-x + 8 ≥ 11

-x ≥ 3

x ≤ -3

Hope this helps! ;)

8 0

3 years ago

Write the equation of the graph in slope intercept form

creativ13 [48]

Answer:

To write a slope-intercept equation from a graph, find the point where the graph crosses the y-axis, b, and the slope, m, and plug them into the equation y=mx+b.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

2 years ago

20 POINTS BRAINLIEST

RSB [31]

Answer:

Step-by-step explanation:

Exponential decay should be in this format A = Ao × e^(-kt)

7 0

3 years ago

find the area of the faded region. Round your answer to the nearest HUNDREDTH. Just put in the answer.​

find the area of the faded region. Round your answer to the nearest HUNDREDTH. Just put in the answer.