Question

In the standard (x,y) coordinate plane, what is the midpoint of the line segment that has endpoint a (3,8) and (1,-4)?

Answer 1

Answer:

$M = (2,2)$

Step-by-step explanation:

Given

$(3,8)$ and $(1,-4)$

Required

Determine the coordinate of the midpoint (M)

This is calculated as thus:

$M = \frac{1}{2}(x_1 + x_2, y_1 + y_2)$

Where

$(3,8)$ -- $(x_1,y_1)$

$(1,-4)$ -- $(x_2,y_2)$

So, we have:

$M = \frac{1}{2}(3 + 1, 8 - 4)$

$M = \frac{1}{2}(4, 4)$

$M = (\frac{1}{2}*4, \frac{1}{2}*4)$

$M = (2,2)$

Hence, the coordinates of the midpoint is (2,2)