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kolbaska11 [484]
3 years ago
9

1. The expression 11x2 - 12x - 10 has ___ terms and a constant of ___.

Mathematics
1 answer:
Maru [420]3 years ago
8 0
#2 is 10x-y because 7x+3x=10xthen your subtracting 2y-y so it would be 10x-y
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G(x)=-3x-8<br>g( )=10<br>what does x equal?​
Nikolay [14]

Answer: X = 24/G

G = 24/x

                     

Step-by-step explanation:

6 0
3 years ago
Which equation has the steepest parabola?
ICE Princess25 [194]

Given:

The equations of parabolas in the options.

To find:

The steepest parabola.

Solution:

We know that, if a parabola is defined as

(y-k)=n(x-h)^2

Then, the greater absolute value of n, the steeper the parabola.

It can be written as

\dfrac{1}{n}(y-k)=(x-h)^2

p(y-k)=(x-h)^2

where p=\dfrac{1}{n}, the smaller absolute value of p, the steeper the parabola.

Now, find the value of |p| for eac equation

For option A, |-0.5|=0.5

For option B, |5|=5

For option C, |8|=8

For option D, |-10|=10

Since, the equation is option A has smallest value of |p|, therefore, the equation (x+2)^2=-0.5(y+3) represents the steepest parabola.

Hence, the correct option is A.

7 0
3 years ago
6. The dimensions of a rectangular garden are 380ft x 250ft. If you want to walk around this garden to make 3 miles for a mornin
SSSSS [86.1K]

Answer:

Step-by-step explanation:

L=3(5280)/(2(380+250))

L=15840/1260

L=12.57

So to walk three miles one must walk around the garden 12.57 times.

7 0
3 years ago
Solve the equation 0.3x-2=0.1(x+20) whats the solution set?
Inga [223]

x = 40/2 = 20 i think thsts the answer if I was wrong you have to right to slap my face

7 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
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