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Dvinal [7]
3 years ago
10

Question 8 of 10

Physics
1 answer:
Alika [10]3 years ago
6 0
B. Venus hope this helps have a great day
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For the new GCSE they aren't giving people the data sheets anymore, sadly.
Art [367]
Ikr. or the equations either. idk what year ur in but I'm in year 10 so will be first year to do it as well
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3 years ago
Rearrange the letters from the following words to reveal a fact about force: FOX ENTERS PINE DEN CROSSWISE. Please use all lette
pogonyaev
<em>FORCE IS EXPRESSED IN NEWTONS.</em>
7 0
3 years ago
Water in its solid state has a specific heat of 2.093 J/g°C. Water in its liquid state has a specific heat of 4.186 J/g°C. Which
vladimir1956 [14]

Answer:

D: The hydrogen bonds between water molecules are more cohesive in the liquid state than in the solid state.

Explanation:

If we assume that there is no phase change due to heating, we know that the temperature change will be proportional to the mass heated, being the proportionality constant that is a quantity which depends on the material, and also represents the resistance of the material to cause a change in the temperature and is called specific heat.

Now, if we are to assume that the mass is the same for the three phases, and that the amount of heat supplied is also the same, the phase with the highest specific heat will therefore possess the lowest temperature change.

At a lower temperature, the hydrogen bonds will be more cohesive than at higher temperatures.

We are told that in it's solid state, it has a specific heat capacity of 2.093 J/g°C while in its liquid state, it has a specific heat capacity of 4.186 J/g°C.

Thus, the hydrogen bonds between water molecules in the liquid state will be less cohesive than in its solid state.

3 0
3 years ago
Read 2 more answers
What is the period of a wave that travels through a spring at 2.5 m/s and has a wavelength of 1.3 meters?​
ruslelena [56]

Answer:

v=(1/f) ×λ

(1/f)= v/λ

(1/f)= 2.5 ÷ 1.3

(1/f)= 1.92 seconds

T = 1.92 seconds

Explanation:

period= 1÷ frequency

T=1/f

7 0
2 years ago
An object is pulled along the ground by exerting a force of 35 pounds a rope that makes a 10° angle with the ground. How much wo
GREYUIT [131]
<h2>Answer:</h2>

Workdone = 601.33 Nm

<h2>Explanation:</h2>

Workdone = Force(F) x horizontal distance(d).

Wordone = F x d

Where F is the horizontal component of the force

Force = 35 pounds

Recall that;

1 pound force = 4.4N

=> 35 pounds = 35 x 4.4N = 154N

=> Force = 154N

But since the rope makes a 10⁰ angle with the ground,

The horizontal component of the force F is  Force x  cos10⁰

=> F = 154 cos 10⁰

=> F = 154 x 0.9848

=> F = 151.66N

Horizontal distance (d) = 13 feet

Recall that;

1 foot = 0.305m

=> 13 feet = 13 x 0.305m = 3.965m

=> d = 3.965m

=> Substituting the values of F and d into the equation above, we have;

Workdone = F x d

Workdone = 151.66N x 3.965m

Workdone = 601.33Nm

8 0
4 years ago
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