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3 years ago

Find the value of an investment of $15,000 for 13 years at an annual interest rate of 4.55% compounded continuously.

Mathematics

1 answer:

atroni [7]3 years ago

4 0

Answer:

A = $27100.5

Step-by-step explanation:

We are given;

Principal: P = $15,000

Interest rate: r = 4.55% = 0.0455

Time in years: t = 13 years

The formula for the value of the investment after t years of continuous compounding is;

A = P(e^(rt))

A = 15000(e^(0.0455 × 13))

A = 15000 × 1.8067

A = $27100.5

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antiseptic1488 [7]

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2 years ago

Simplify the expressions.

emmasim [6.3K]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Write a problem in which $180 would be a reasonable answer

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Step-by-step explanation: I didn't know what you needed. I'm sorry if that's not it, but hope it helps.

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2 years ago

Hi please answer and you dont NEED to show work but if u do i will give brainliest

Advocard [28]

Answer:

$y=-\frac{2}{5} -1$

Step-by-step explanation:

So first thing is that slope intercept form is setup like this

y=mx+b

m=slope

b=y intercept

the slope is change in y over change in x

as y goes down 2 x goes up 5

so the slope is -2/5

the y intercept is at (0,-1) so the y intercept is -1

therefore the answer is

$y=-\frac{2}{5} -1$

have a great day :)

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2 years ago

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If a =5 and b=3 what is the value of the 2a-3b+3a

34kurt

Answer:

If a = 5 and b = 3, then that means 2a - 3b + 3a = 16

Step-by-step explanation:

2a - 3b + 3a

(2×5) - (3×3) + (3×5)

10 - 9 + 15 = 16

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3 years ago