400,000,000 + 30,000,000 + 200,000 + 90,000 +100
A = 1/2 bh = 1/2 (3)(4) = 12/2 = 6
answer is B. 6 square units
Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Answer:

Step-by-step explanation:
Solve

For x=-1/2 and y=-3
substitute the value of x and the value of y in the expression above

Remember that

so

Convert to mixed number
