Will give brainlist if correct! Thanks!

Grapes are 2.55 per pound and on two separate occasions Dana went to the store to

fomenos

Answer: $11.48

Step-by-step explanation:

First of all, you have to multiply 3.25 by 2.55 because the grapes are 2.55 per pound. That makes 8.2875 for the first occasion. Next, you have to multiply 1.25 by 2.55 for the second occasion. That makes 3.1875. You then have to add 8.2875 and 3.1875. You get 11.47500, and that rounded to the nearest cent is $11.48.

8 0

3 years ago

What is the value of h when the function is converted to vertex form?

elena-s [515]

Answer: h=7

Step-by-step explanation:

By definition the function in vertex form is:

$f(x)=a(x-h)^{2}+k$

Where (h,k) is the vertex of the parabola.

You must group the terms that contain the same variable in the function:

$f(x)=(x^{2}-14x)+29$

Complete the square as following:

$f(x)=(x^{2}-14x+49)+29-49$

Now you must rewrite it as following:

$f(x)=(x-7)^{2}-20$

Then:

h=7

4 0

3 years ago

Read 2 more answers

PLEASE HELP PLEASE

astraxan [27]

Answer:the answer is

Step-by-step explanation:c

5 0

3 years ago

Read 2 more answers

2) Which of the following is the complete factorization of 6x^2? A. 6⋅x⋅x B. 2⋅3⋅x ^2 C. 2⋅3⋅x⋅x

Elena-2011 [213]

Answer:

C. 2• 3 • x • x

Step-by-step explanation:

Not sure but that's what I would guess

5 0

4 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago