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4 years ago

Solve for x: -3(x+3)=-3(x+1)-5

Mathematics

1 answer:

masya89 [10]4 years ago

3 0

-3(x+3)=-3(x+1)-5
-3x-9=-3x-3-5
-3x-9=-3x-8
The question has no solution

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Mis Meyer's paid $3600 all together for the equipment, furniture and decorations for her restaurant. The equipment cost $500 mor

Tju [1.3M]

Answer:

The equipment will cost $1740.

Step-by-step explanation:

Let the Cost of equipment, furniture and decoration be x, y and z.

Now, According to question,

x + y + z = 3600 ...... (1) (cost of all items)

x = 500 + y (∵ equipment cost 500 more than furniture)

and y = 2z ( ∵ furniture twice as much as decoration)

so, z = y/2

Now substituting the value of x and z in eq (1)

$x + y + z = 3600$

$500 + y + y + \frac{y}{2} = 3600$

$2y + \frac{y}{2} = 3600 - 500$

$\frac{5y}{2} = 3100$

$y = \frac{3100\times 2}{5} = 1240$

So, the cost of furniture (y) = 1240

∴ Cost of equipment = y + 500 = 1240 + 500 = 1740

Therefore the cost of equipment was $1740.

3 0

3 years ago

When 6x³-3x²+4x+1 is divided by 2x-1 the result is ?

Tasya [4]

The result is

3x^2 + 2 + 3/2x-1

3 0

3 years ago

What is this I need help

omeli [17]

2) 3 is the answer of your questions

4 0

3 years ago

Solve the equation: -17-2x=6-x Solve for x.

irinina [24]

-17-2x=6-x
-2x + x = 6 + 17
-x = 23
x = -23

7 0

4 years ago

Read 2 more answers

What is the value of c such that the line y=2x+3 is tangent to the parabola y=cx^2

satela [25.4K]

The value of $c$ such that the line $y = 2\cdot x + 3$ is tangent to the parabola $y = c\cdot x^{2}$ is $-\frac{1}{3}$ .

If $y = 2\cdot x + 3$ is a line tangent to the parabola $y = c\cdot x^{2}$ , then we must observe the following condition, that is, the slope of the line is equal to the first derivative of the parabola:

$2\cdot c \cdot x = 2$ (1)

Then, we have the following system of equations:

$y = 2\cdot x + 3$ (1)

$y = c\cdot x^{2}$ (2)

$c\cdot x = 1$ (3)

Whose solution is shown below:

By (3):

$c =\frac{1}{x}$

(3) in (2):

$y = x$ (4)

(4) in (1):

$y = -3$

$x = -3$

$c = -\frac{1}{3}$

The value of $c$ such that the line $y = 2\cdot x + 3$ is tangent to the parabola $y = c\cdot x^{2}$ is $-\frac{1}{3}$ .

We kindly invite to check this question on tangent lines: brainly.com/question/13424370

3 0

3 years ago