The process of sediments being compacted and cemented to form sedimentary rocks is called

An ideal parallel-plate capacitor having circular plates of diameter D that are a distance d apart stores energy U when it is co

Stella [2.4K]

Answer: $\sqrt{3}D$

Explanation:

Given

Diameter of Plates is D

distance between Plates is d

Energy Stored in the Plates is U

Suppose fixed Potential is V

Energy is given by

$U=\frac{1}{2}CV^2$

where C=capacitance

$C=\frac{\epsilon A}{d}$

where A=area of Plates

$A=\frac{\pi D^2}{4}$

Thus $C=\frac{\epsilon \cdot \pi \cdot D^2}{4d}$

Keeping all other factors as same

$U\propto D^2----1$

For triple the Energy

$3U\propto (D')^2-----2$

divide 1 and 2 we get

$\frac{U}{3U}=\frac{D^2}{D'^2}$

$D'=\sqrt{3}D$

Thus the diameter should be change to $\sqrt{3}$ times of original value

3 0

3 years ago

Which equation would you use to solve the following problem?

aivan3 [116]

The correct answer to the question is : C)The problem is asking to solve for work; W = F × d

EXPLANATION:

As per the question, the distance covered by the object d = 29 m.

The force that acts on the object is F = 289 N.

We are asked to choose the correct equation for work done.

Work is said to be done on a body or by a body if the applied force has a component along the direction of displacement.

Mathematically work done W = force × displacement

= F × d

As per the question, we are given distance covered and applied force.

Hence, the correct equation for calculating work done by the object is equation C.

6 0

3 years ago

Read 2 more answers

What are the two ways that devices can be connected in a circuit?

Marysya12 [62]

That two ways are known as:

1) Series connection

2) Parallel connection

5 0

4 years ago

Which of the following is true for both gas planets and terrestrial planets? Please Answer ASAP!!

Veseljchak [2.6K]

I think the answer is B. All planets rotate on an axis except Venues and Uranus and only Uranus has some what of a core of ice, and they for sure don’t all have rings. So I say the answer is B

3 0

3 years ago

Recall the relationship between the charge on a capacitor and the potential difference across the capacitor. Use this relationsh

charle [14.2K]

Answer:

Answer in explanation.

Explanation:

The relationship between the charge on the capacitor and the potential difference across it is given as follows:

$Q = CV$

where,

Q = Charge on the Capacitor

C = Capacitance of the Capacitor

V = Potential Difference across the Capacitor

This relationship can be used to find the charge on a capacitor, using the voltmeter, as follows:

<u>The potential difference can be measured through the voltmeter. And the capacitance of the capacitor is a known constant value. Therefore, the charge can be found by taking product of both.</u>

8 0

3 years ago