This force is centripetal force. it is the force that will hold the rider in the circular path and prevent him from skidding off. It is equal to the friction between the tyres and the road if no banking has been done on the road at the corner.
Answer:
![i = 2.84 \times 10^{-3} A](https://tex.z-dn.net/?f=i%20%3D%202.84%20%5Ctimes%2010%5E%7B-3%7D%20A)
Explanation:
As we know that current density is ratio of current and area of the crossection
now we have
![J = \frac{di}{dA}](https://tex.z-dn.net/?f=J%20%3D%20%5Cfrac%7Bdi%7D%7BdA%7D)
so the current through the wire is given as
![i = \int J dA](https://tex.z-dn.net/?f=i%20%3D%20%5Cint%20J%20dA)
now we have
![i = \int_{0.921R}^R J dA](https://tex.z-dn.net/?f=i%20%3D%20%5Cint_%7B0.921R%7D%5ER%20J%20dA)
here we have
![J = (3.25 \times 10^8)r^2](https://tex.z-dn.net/?f=J%20%3D%20%283.25%20%5Ctimes%2010%5E8%29r%5E2)
now plug in the values in above equation
![i = \int_{0.921R}^R (3.25 \times 10^8)r^2 2\pi r dr](https://tex.z-dn.net/?f=i%20%3D%20%5Cint_%7B0.921R%7D%5ER%20%283.25%20%5Ctimes%2010%5E8%29r%5E2%202%5Cpi%20r%20dr)
now we have
![i = \int_{0.921R}^R 2\pi (3.25 \times 10^8)r^3 dr](https://tex.z-dn.net/?f=i%20%3D%20%5Cint_%7B0.921R%7D%5ER%202%5Cpi%20%283.25%20%5Ctimes%2010%5E8%29r%5E3%20dr)
![i = (2.04 \times 10^9) \frac{r^4}{4}](https://tex.z-dn.net/?f=i%20%3D%20%282.04%20%5Ctimes%2010%5E9%29%20%5Cfrac%7Br%5E4%7D%7B4%7D)
now plug in both limits as mentioned
![i = (2.04 \times 10^9)(\frac{R^4}{4} - \frac{(0.921R)^4}{4})](https://tex.z-dn.net/?f=i%20%3D%20%282.04%20%5Ctimes%2010%5E9%29%28%5Cfrac%7BR%5E4%7D%7B4%7D%20-%20%5Cfrac%7B%280.921R%29%5E4%7D%7B4%7D%29)
![i = (2.04\times 10^9)(0.07 R^4)](https://tex.z-dn.net/?f=i%20%3D%20%282.04%5Ctimes%2010%5E9%29%280.07%20R%5E4%29)
here R = 2.11 mm
![i = (2.04 \times 10^9)(0.07 (2.11 \times 10^{-3})^4)](https://tex.z-dn.net/?f=i%20%3D%20%282.04%20%5Ctimes%2010%5E9%29%280.07%20%282.11%20%5Ctimes%2010%5E%7B-3%7D%29%5E4%29)
![i = 2.84 \times 10^{-3} A](https://tex.z-dn.net/?f=i%20%3D%202.84%20%5Ctimes%2010%5E%7B-3%7D%20A)
Answer:
A bird flies 75m in 15s.Calculate its speed
A concave lens can only form a virtual image. The correct option among all the options that are given in the question is the third option or option "C". Concave lenses are mostly thinner in the middle compared to its edges. I hope that this answer has come to your help.
When the object slides across the rough surface some of its potential energy will be lost to friction.
<h3>Conservation of mechanical energy</h3>
The law of conservation of mechanical energy states that the total mechanical energy of an isolated system is always constant.
M.A = P.E + K.E
When the object slides across the rough surface, some of the potential energy of the object will be converted into kinetic energy while the remaining potential energy will be converted into thermal energy due to frictional force of the rough surface.
P.E = K.E + thermal energy
Learn more about conservation of energy here: brainly.com/question/166559