First, find the amount of time for the dart to hit the board using this equation: t = d/v
t = 2 m/ 15 m/s = 0.133 s
Then, find the height the dart has fallen from its initial point using this equation: h = 0.5gt²
h = 0.5(9.81 m/s²)(0.133 s)² = 0.0872 m or 8.72 cm
Since the diameter of the bull's eye is only 5 cm, and you started at the same level of the top of the bull's eye, that means the maximum allowance would only be 5 cm. Since it exceeded to 8.72 cm, it means that <em>Veronica will not hit the bull's eye.</em>
Yes they do because they just have to
Answer:
The corresponding magnetic field is
Explanation:
From the question we are told that
The electric field amplitude is ![E_o = 611\ V/m](https://tex.z-dn.net/?f=E_o%20%20%20%3D%20%20611%5C%20%20V%2Fm)
Generally the magnetic field amplitude is mathematically represented as
![B_o = \frac{E_o }{c }](https://tex.z-dn.net/?f=B_o%20%20%3D%20%20%5Cfrac%7BE_o%20%7D%7Bc%20%7D)
Where c is the speed of light with a constant value
![c = 3.0 *0^{8} \ m/s](https://tex.z-dn.net/?f=c%20%3D%203.0%20%2A0%5E%7B8%7D%20%5C%20m%2Fs)
So
![B_o = \frac{611 }{3.0*10^{8}}](https://tex.z-dn.net/?f=B_o%20%20%20%3D%20%20%5Cfrac%7B611%20%7D%7B3.0%2A10%5E%7B8%7D%7D)
![B_o = 2.0 4 *10^{-6} \ Vm^{-2} s](https://tex.z-dn.net/?f=B_o%20%20%20%3D%20%202.0%204%20%2A10%5E%7B-6%7D%20%5C%20%20Vm%5E%7B-2%7D%20s)
Since 1 T is equivalent to ![V m^{-2} \cdot s](https://tex.z-dn.net/?f=V%20%20m%5E%7B-2%7D%20%5Ccdot%20%20s)
![B_o = 2.0 4 *10^{-6} \ T](https://tex.z-dn.net/?f=B_o%20%20%3D%20%202.0%204%20%2A10%5E%7B-6%7D%20%5C%20T)
Answer:
the new resister is 11 ohms.
Explanation:
Set it up like this.
1/x + 1/1.1 = 1 Subtract 1/1.1 from both sides
1/x = 1 - 1/1.1
1 - 1/1.1 = 1/11
1/x = 1/11 Cross multiply
11 = x
If 1/11 bothers you, you could do it it another way.
1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1 Multiply top and bottom by 10
0.1*10/(1.1 * 10 ) = 1 / 11