Butterfly one I forgot the name metapods evolution
What is the problem what am I supposed to do?
Answer:
The correct answer to the following question will be "Adaptive Optics".
Explanation:
- AO (Adaptive Optics) is a technique used to enhance optical system performance by reducing the impact of incoming gravitational wave distortions by compressing a mirror to compensate for the distortion.
- It operates by calculating and compensating for defects in a wave-front with a system that corrects these errors as a deformable mirror or even a liquid crystal collection.
- It is a technique that can make it possible for a single ground-based telescope to get images as clear as that of the Hubble Space Telescope.
- Certain methods can achieve power resolution that exceeds the limit set by atmospheric distortion, for example, Aperture synthesis, Lucky imaging, and Speckle imaging.
Therefore, Adaptive Optics is the right answer.
Answer:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int SIZE_LIST = 4;
int[] keysList = new int[SIZE_LIST];
int[] itemsList = new int[SIZE_LIST];
int i;
keysList[0] = 13;
keysList[1] = 47;
keysList[2] = 71;
keysList[3] = 59;
itemsList[0] = 12;
itemsList[1] = 36;
itemsList[2] = 72;
itemsList[3] = 54;
/* Your solution goes here */
for ( i = 0; i < SIZE_LIST; i++){
if (keysList[i]>50){
System.out.println(itemsList[i] + " "); } }
System.out.println("");
}
}
Explanation:
I will explain the whole program flow.
- There are two arrays here
- The first list (keysList) contains the following elements:
13 element at first position of the array (0th index)
47 element at second position of the array (1st index)
71 element at third position of the array (2nd index)
59 element at fourth position of the array (3rd index)
- The other list (itemsList) contains the following elements:
12 element at first position of the array (0th index)
36 element at second position of the array (1st index)
72 element at third position of the array (2nd index)
54 element at fourth position of the array (3rd index)
- The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
- Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
- So the program control enters the body of the loop.
- In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
- In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
- IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
- In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
- So the output of the above program is:
72
54
Edge computing be used to increase sustainability With Edge Computing the number of records traversing the network can be reduced greatly, freeing up bandwidth.
<h3>How is part computing sustainable?</h3>
Data centers devour an expected 2 hundred terawatt-hours (TWh) of power every year–extra than the power intake of a few countries. They additionally produce an expected 2% of all worldwide CO2 emissions. Edge Computing reduces network site visitors and records centre usage.
Data centres devour an expected 200 terawatt-hours (TWh) of power every year–extra than the power intake of a few countries. They additionally produce an expected 2% of all worldwide CO2 emissions.
Read more about the sustainability:
brainly.com/question/25350238
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