Find total number of integers.

Find how many integers is divisible by 2.

Eliminate even numbers.
11, 13, 15,..., 57, 59
This array contains 51 - 26 = 25 numbers.
Eliminate numbers before the first number divisible by 3 and after the last number divisible by 3.
15, 17, 19,..., 55, 57
This array contains 25 - 3 = 22 numbers.
Now we should eliminate numbers divisible by 3: 15, 21, 27...

There are 8 such numbers.
Therefore, there are 25 - 8 = 17 numbers that <span>can be evenly divided by neither 2 nor 3</span>
Answer:
second option
Step-by-step explanation:
Given
f(x) = (x - 7)(x + 4)(3x - 2)
To find the zeros let f(x) = 0, that is
(x - 7)(x + 4)(3x - 2) = 0
Equate each factor to zero and solve for x
x - 7 = 0 ⇒ x = 7
x + 4 = 0 ⇒ x = - 4
3x - 2 = 0 ⇒ 3x = 2 ⇒ x = 
zeros are x = - 4, x =
, x = 7
You can set up an system of equations
x=2y+8
x-y=25
Substitute x in to the second equation
2y+8-y=25
y+8=25
y=17
Substitute the y back in to the first equation.
x=2(17)+8=42
Answer is <span>A.
{2, 4}
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Answer:
$ (C/t ) × 5
= $ 5C/t
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