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3 years ago

11

What's 2.5 meters to millimeters ????

2 answers:

Katyanochek1 [597]3 years ago

7 0

Answer:

2.5 meters = 2500 millimeters

Hope this helps :)

irga5000 [103]3 years ago

4 0

answer

2500

because it's mm

and you just have to add 2 more place values

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What is the total number of atoms in the molecule HNO3?

melomori [17]

Answer:

We know that, composition of HNO3 is Hydrogen, Nitrogen and oxygen. Total number of atoms = 3+1+1=5 atoms are present in 1 molecule of HNO3.

5 0

3 years ago

100 PTS IM DESPERATE NEED BY TOMMOROW

faust18 [17]

Answer:

rest will do later mom is calling me plz understand promise will do it

Explanation:

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3 years ago

(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe

Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration $C_o$ = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

$time (t) = \dfrac{V}{Q}$

$time (t) = \dfrac{200}{0.3}$

$time (t) = 666.66 \ sec$

$time (t) = \dfrac{666.66 }{3600} hrs$

$time (t) = 0.185 hrs$

$\text{Using First Order Reaction:}$

$\dfrac{dc}{dt}=kc$

where;

$t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)$

$0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)$

$0.942 = \Big ( \dfrac{200}{C_e}- 1 \Big)$

$1+ 0.942 = \Big ( \dfrac{200}{C_e} \Big)$

$\dfrac{200}{C_e} = 1.942$

$C_e = \dfrac{200}{1.942}$

$\mathbf{C_e = 102.98 \ mg/l}$

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

$t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)$

$\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)$

$\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)$

$V_{PFR} =0.196(0.663)*0.3*3600$

$V_{PFR} = 140.34 \ m^3$

The volume of the PFR is ≅ 140 m³

3 0

3 years ago

How many molecules are there in 218.4 grams of C0CI2?

Alex Ar [27]

Answer:

10.24 ×10²³ molecules

Explanation:

Given data:

Mass of COCl₂ = 218.4 g

Number of molecules = ?

Solution:

Number of moles of COCl₂:

Number of moles = mass/molar mass

Number of moles = 218.4 g/ 129.84 g/mol

Number of moles = 1.7 mol

1 mole contain 6.022×10²³ molecules.

1.7 mol × 6.022×10²³ molecules / 1mol

10.24 ×10²³ molecules

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3 years ago

Bailey swam 0.86 km, biked

____ [38]

Answer:

2,751 Meters.

Explanation:

0.86 + 22.4 + 4.25 = 27.51 km.

Convert that to meters which gives you 2,751 meters.

7 0

3 years ago