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seropon [69]
3 years ago
6

Number 16 pls answer

Chemistry
1 answer:
barxatty [35]3 years ago
4 0

Answer:it’s D

Explanation:

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A.) The number of electron shells increases.
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What is the density of an unknown object that has a mass of 5.0 g and volume of 20<br> ml?
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Answer:

Density=mass / volume.

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0.25g/cm^3.

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Cryolite (Na3AlF6) is used in the production of aluminum from its ores. It is made by the reaction 6 NaOH 1 Al2O3 1 12 HF 8n 2 N
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<u>Answer:</u> The mass of cryolite produced in the reaction is 1181.8 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of aluminium oxide = 287 g

Molar mass of aluminium oxide = 102 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium oxide}=\frac{287g}{102g/mol}=2.814mol

The given chemical reaction follows:

6NaOH+Al_2O_3+12HF\rightarrow 2Na_3AlF_6+9H_2O

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 2.814 moles of aluminium oxide will produce = \frac{2}{1}\times 2.814=5.628mol of cryolite

Now, calculating the mass of cryolite by using equation 1:

Moles of cryolite = 5.628 moles

Molar mass of cryolite = 210 g/mol

Putting values in equation 1, we get:

5.628mol=\frac{\text{Mass of cryolite}}{210g/mol}\\\\\text{Mass of cryolite}=(5.628mol\times 210g/mol)=1181.8g

Hence, the mass of cryolite produced in the reaction is 1181.8 g

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3 years ago
Consider the following reaction at equilibrium: C(s)+H2O(g)⇌CO(g)+H2(g) Predict whether the reaction will shift left, shift righ
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'Answer:

a) C is added to the reaction mixture.      "shift right"

b) H₂O is condensed and removed from the reaction mixture.    "shift left"

c) CO is added to the reaction mixture.        "shift left"

d) H₂ is removed from the reaction mixture.      "shift right"

Explanation:

  • <em>Le Châtelier's principle</em><em> states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

<em />

<u><em>a) C is added to the reaction mixture:</em></u>

Adding C(s) will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the increase in the concentration of C by addition.

<em>So, the reaction shift right.</em>

<em></em>

<u><em>b) H₂O is condensed and removed from the reaction mixture:</em></u>

Removing H₂O will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the decrease in the concentration of H₂O by removal.

<em>So, the reaction shift left.</em>

<em></em>

<u><em>c) CO is added to the reaction mixture:</em></u>

Adding CO will increase the concentration of the products side, so the reaction will be shifted to the left side to suppress the increase in the concentration of CO by addition.

<em>So, the reaction shift left.</em>

<em></em>

<u><em>d) H₂ is removed from the reaction mixture:</em></u>

Removing H₂ will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the increase in the concentration of H₂ by removal.

So, the reaction shift right.

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