Answer:
Parts of a transverse wave include:
Crest - the highest point on the wave
Trough - the lowest point on the wave
Wavelength - the distance from one crest to the next crest, or one trough to the next trough
Amplitude - the displacement of the wave from the midpoint to the highest point (crest) or the lowest point (trough)
Explanation:
Use the internet Brother
Power = (work done) / (time to do the work)
Work done = (force to lift the object) x (distance lifted)
In this question, the force is the (weight of the basket)+(your weight).
Work done = (weight of basket+you) x (3 meters)
Time to do the work = 6 seconds.
Power = (weights x 3 meters) / (6 seconds)
<em>Power = (1/2)·(weight of the basket+you, in Newtons) watts</em>
Answer:
93.4 kg
Explanation:
Draw a free body diagram. There are three four forces:
Weight force mg pulling down,
Normal force N pushing up,
Friction force Nμ pushing left,
Applied force F pulling up and to the right, 30.0° above the horizontal.
Sum of forces in the y direction:
∑F = ma
N + F sin 30.0° − mg = 0
N = mg − ½ F
Sum of forces in the x direction:
∑F = ma
F cos 30.0° − Nμ = 0
½√3 F = Nμ
Substitute:
½√3 F = (mg − ½ F) μ
½√3 F / μ = mg − ½ F
½√3 F / μ + ½ F = mg
½F (√3 / μ + 1) = mg
m = F (√3 / μ + 1) / (2g)
Plug in values:
m = 410 N (√3 / 0.500 + 1) / (2 × 9.8 m/s²)
m = 93.4 kg
Answer:
37.33m
Explanation:
To calculate the distance using d= 1/2 at², the time taken for this projectile object (ball) must be calculated.
Time of a projectile = 2u sinθ/ g
Where u = velocity = 27m/s
g = 9.8m/s²
θ = 30°
T = 2usinθ/ g
T = 2 × 27 × sin 30°/9.8
T = 54sin30°/9.8
T = 27/9.8
T = 2.755
T = 2.76s
If the time taken for the ball to move is 2.76s, the distance travelled is:
D = 1/2at²
D = 1/2 × 9.8 × 2.76²
D = 1/2 × 9.8 × 7.6176
D = 74.65248/2
D = 37.33m
The horizontal distance the ball travels is 37.33m
