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Nataliya [291]
3 years ago
13

Dimas reads that it takes 270 N to lift a firefighter's equipment. If a firefighter does 5400 J of work carrying the equipment u

p a staircase, how high does the firefighter climb? (Work: W = Fd) 20 m 200 m 5130 m 1,458,000 m
Physics
2 answers:
Alex787 [66]3 years ago
7 0

Answer:

h = 20 m

Explanation:

Given that,

Force to lift a firefighter's equipment, F = 270 N

Work done, W = 5400 J

We need to find the height climbed by the firefighter. We know that,

Work done, W = Fd

So,

d=\dfrac{W}{F}\\\\d=\dfrac{5400}{270}\\\\d=20\ m

So, the firefighter climb from a height of 20 m.

hodyreva [135]3 years ago
7 0

Answer:

Its A

Explanation: I got it right on Edge *lip bite*

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According to Ohm’s law, which combination of units is the same as the unit for resistance? volt ÷ ampere ampere × volt volt + am
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Answer:

volt ÷ ampere

Explanation:

The mathematical form of Ohms law is given by :

V = IR

Where V is voltage

I is current

R is resistance

R=\dfrac{V}{I}

The unit of voltage is volt and that of current is ampere

Unit of resistance :

R=\dfrac{\text{volt}}{\text{ampere}}

So, volt ÷ ampere is the same as the unit of resistance. Hence, the correct option is (a).

6 0
3 years ago
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A 6 kg block is sliding down a horizontal frictionless surface with a constant speed of 5 m/s. It then slides down a frictionles
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Answer:

5in

Explanation:

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4 years ago
A snowball accelerates at
ANTONII [103]

Answer:

0. 1226495726kg

Explanation:

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Mathematically,

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Substituting the values into the equation

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8 0
3 years ago
I need help finding the answer
miss Akunina [59]

Speed = (distance) / (time)

Speed = (2.3 m) / (3 sec)

Speed = (2.3/3) (m/s)

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5 0
3 years ago
A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequenc
max2010maxim [7]

The frequency of oscillation is 2.153 Hz

What is the frequency of spring?

Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.

For the mass-spring system in this problem,

The Frequency of spring is calculated with the equation:

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

Where,

f = frequency of spring

k = spring constant = 64 N/m

m = mass attached to spring = 350g = 0.350 kg

a = maximum acceleration = 5.3 m/s^2

Substituting the values in the equation,

f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }

f = \frac{1}{2\pi } ( 13.522)

f = 2.1535 Hz

Hence,

The frequency of oscillation is 2.153 Hz

Learn more about frequency here:

<u>brainly.com/question/13978015</u>

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