For the galvanic cell at 298 k zn(s) 2in2 (aq)zn2 (aq) 2in (aq) eocell = 0.36 v what is the equilibrium constant, k?
1 answer:
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Explanation:
It is given that,
Initially, the jogger is at rest u₁ = 0
He accelerates from rest to 4.86 m, v₁ = 4.86 m
Time, t₁ = 2.43 s
A car accelerates from u₂ = 20.6 to v₂ = 32.7 m/s in t₂ = 2.43 s
(a) Acceleration of the jogger :
a₁ = 2 m/s²
(b) Acceleration of the car,
a₂ = 4.97 m/s²
(c) Distance covered by the car,
d₁ = 5.904 m
Distance covered by the jogger,
d₂ = 64.73 m
The car further travel a distance of, d = 64.73 m - 5.904 m = 58.826 m
Hence, this is the required solution.
speed of tortoise is given as v1 = 0.14 m/s
speed of hare is given as v2 = 20*0.14 = 2.8 m/s
now let say the total length of the path is "d"
so the total time taken by the tortoise to cover this
now given that hare took rest for 1 min
so total time of run for hare is (t - 60)s
so the distance that hare covered is given by
now by above two equations
and the time t is given by
so part a)
t = 63 s
part b)
d = 8.82 m