Answer:
Yes, it does, although only physically and not chemically.
Explanation:
If a volume of gas is way spread out, it won't collide with the other gas particles as often, reducing pressure and temperature because they lose kinetic energy to their surroundings when they don't collide.
If it is compressed, it increases temperature and pressure because the gas particles collide with each other and the walls of the container way more often than if they had more space.
Hope this answers your question.
P.S.
Fun fact, gas particles are actually moving at 300-400 meters per second at room temperature, they only slow down to walking speed at very low temperatures, like 10 Kelvin
Answer:
Name of the compound is Nitrogen triiodide.
Explanation:
According to the IUPAC rules, to naming of the compound the following formula can be applied.
Prefix + Name of first element + Base name element of second element + Suffix.
The given compound - 
Name of first element- Nitrogen
Base name element of second element - Iodine
Suffix = 3 = tri
Here, iodine is in ionic form therefore, it becomes iodide. and then suffix will be added in front of the halogen.
Therefore, name of the compound will be Nitrogen triiodide..
Answer:
10.335
Explanation:
An object was carefully weighed on three different balances
Each of these balances were zeroed before weighing
The masses that were weighed are as follows
10.35 g , 10.355 g, 10.30 g
Therefore the average value of these measurements can be calculated as follows
The total number of mass is 3
= 10.30 + 10.355 + 10.30/3
= 31,005/3
= 10.335
Hence the average value of these measurements is 10.335
Answer:
In oxidation reduction reactions, one species gets reduced by taking on electron(s) and another species gets oxidized by losing electrons. They also flow by a wire
Explanation:
Answer:
Explanation:
Hello,
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
Afterwards, the mass of ice that can be melted is computed by:
So we solve for moles with the proper units handling:
Finally, with the molar mass of water we compute the mass:
Best regards.
