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allochka39001 [22]
4 years ago
5

In practice, a good insulator In practice, a good insulator A. slows heat flow. B. speeds negative heat flow. C. stops heat flow

. D. all of the above
Physics
1 answer:
photoshop1234 [79]4 years ago
7 0

Answer:

<h2>The answer is  </h2><h2>A. slows heat flow.</h2>

Explanation:

 An insulator is a material that impedes the movement of heat or electric current from flowing.

Theoretically good heat insulators stops the movement of heat, while practically this insulation can only be slowed down.

Hence from the options listed the correct answer practically is

<h2>  A. slows heat flow.</h2>
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Explanation:

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3 years ago
Arianna is experimenting with different materials to see which one will
sp2606 [1]

Answer:

Concrete

Explanation:

The speed at which sound propagates is medium dependent. As one of the forms of mechanical waves, sound requires a material medium for propagation from place to place.

  • Sound travels with the least speed in air because air particles are far apart and they are randomized.
  • Sound travels with the greatest speed in solids. Concrete is the only solid material given in the choice.

The speed of sound increases from air to liquid and to solid.

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3 years ago
Como sacar velocidad final sin tener el tiempo
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3 years ago
In Young’s two slit experiment, the first dark fringe above the central bright fringe occurs at an angle of 0.44˚. What is the r
melomori [17]

Answer:

d / λ = 26.7

Explanation:

In Young's double slit experiment, constructive interference is described by the expression

   d sin θ = m λ

In the case of destructive interference we must add half wavelength (λ/2)

   d siyn θ = (m + ½) λ

Let's clear

    d / λ = (m + ½) / sin θ

Let's calculate

   d / λ = (2+ ½) / sin 5.4

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8 0
3 years ago
Consider a box with two gases separated by an impermeable membrane. The membrane can move back and forth, but the gases cannot p
padilas [110]

Answer:

The answer is "0.3336\ m^3"

Explanation:

Using the Promideal gas law:

P_A=P_B\\\\P_A(V_A-\eta_A b)= \eta_A RT......(1)\\\\P_B V_B=\eta_B \bar{R}T........(2)\\\\From (1) \zeta (2)\\\\  

\frac{\eta_A}{V_A-\eta_A b}=\frac{\eta B}{V B}\\\\  \frac{V A- \eta_A b}{V B}=\frac{\eta A}{\eta B }\\\\  \frac{V A-b}{V B}=\frac{1}{2}\\\\V A+V B=1\\\\V B =1- V A\\\\\frac{V A-b}{1-V A}=\frac{1}{2}\\\\2V A-2b=1-V A\\\\3 V A=1+2b\\\\V A=\frac{1+2b}{3}\\\\

      =\frac{1+2(4\times 10^{-4})}{3}\\\\=0.3336\ m^3

8 0
3 years ago
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