A 40 N crate rests on a rough horizontal floor. A 12 N horizontal force is then applied to it. If the coecients of friction are
μs=0.5 and μk=0.4, the magnitude of the frictional force on the crate is:
1 answer:
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Answer:
length of selfie-stick is 1.62 m
Explanation:
Given data
image size h1 = 5 mm = 5 × m
focal length = 4 mm = 4 × m
distance h2 = 2.032 m
to find out
How long of a selfie-stick
solution
here we find first magnification
that is M = h1 /h2
M = 5 × / 2.032
M = 2.46 ×
and we know M = p/q
so p = Mq = 2.46 × q
so we apply lens formula
1/f = 1/p - 1/q
1/ 4 × = 1 / 2.46 ×
q - 1/q
q = 1.622 m
so length of selfie-stick is 1.62 m