Non- mechanical wave does not need matter to carry energy.
e.g:- Light
Think of a wedge as something you put in between objects, so it is a separates objects
Answer:
The tennis ball will have more kinetic energy
Explanation:
It will have more kinetic energy because the tennis ball is more heavier than a wiffle ball. Furthermore, objects that are heavy will have more kinetic energy than objects that are light. Therefore, the tennis ball is the correct answer.
Answer:
19.99 kg m²/s
Explanation:
Angular Momentum (L) is defined as the product of the moment of Inertia (I) and angular velocity (w)
L = m r × v.
r and v are perpendicular to each other,
where r = lsinθ.
l = 2.4 m
θ= 34°
g = 9.8 m/s² and m = 5 kg
resolving using newtons second law in the vertical and horizontal components.
T cos θ − m g = 0
T sin θ − mw² lsin θ = 0
where T is the force with which the wire acts on the bob
w = √g / lcosθ
= √ 9.8 / 2.4 ×cos 34
= 2.2193 rad/s
the angular momentum L = mr× v
= mw (lsin θ)²
= 5 × 2.2193 (2.4 ×sin 34°)²
=19.99 kg m²/s
Answer:
The heat flows into the gas during this two-step process is 120 cal.
Explanation:
Given that,
Number of moles = 3
Heat capacity at constant volume = 4.9 cal/mol.K
Heat capacity at constant pressure = 6.9 cal/mol.K
Initial temperature = 300 K
Final temperature = 320 K
We need to calculate the heat flow in to gas at constant pressure
Using formula of heat

Put the value into the formula


We need to calculate the heat flow in to gas at constant volume
Using formula of heat

Put the value into the formula


We need to calculate the heat flows into the gas during two steps
Using formula of total heat



Hence, The heat flows into the gas during this two-step process is 120 cal.