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expeople1 [14]
3 years ago
6

I need help please! I'm really bad at math!

Mathematics
2 answers:
sineoko [7]3 years ago
5 0

Answer:

Sorry im not good at diameters

Step-by-step explanation:

hopefully  this helps. since its divided by 2 x would be 4 and y would be 2.5

irakobra [83]3 years ago
5 0
Scale factor of 3. x = 8/3 or 2.66667 and y = 5/3 or 1.66667
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Can the following numbers be converted to fraction form?
Oxana [17]

Answer:

34.333... can

45.543... can

and 0.3497... cannot

Step-by-step explanation:

7 0
3 years ago
There’s a [Picture] can you guys help me!!?
AlekseyPX

Answer:

x<32 (i thik is what you want)

Step-by-step explanation:

if x/8+1<3

x has to be less the 4*8, which is 32.

so x<32

3 0
3 years ago
What is 6x-5&gt;8x+7 but a line under the greater than sign
Ad libitum [116K]
X<-6 with the line under it is the answer, you would flip the sign when u divide

7 0
4 years ago
0.1x+0.2y=-1;0.5x-0.9y=6.4
Harman [31]
.1x+.2y=-1
.5x-.9y=6.4

×-5 equation .1x+.2y=-1

-.5x-y=5
.5x-.9y=6.4

solve by elimination

-1.9y=11.4
÷-1.9 both sides
y=-6

solve for X

.1x+.2 (-6)=-1
.1x-1.2=-1
+1.2 both sides
.1x=.2
÷ 1 both sides
x=2

plug into 2nd equation to see if it's true

x=2
y=-6

0.5(2)-0.9(-6)=6.4
1+5.4=6.4
6.4=6.4 answers hold true
4 0
4 years ago
Find the equation of the normal to the curve y=x^2-2x^2-4x+1 at thepoint (-1,2)​
balandron [24]

Answer:

y=-\frac{1}{3}x+\frac{5}{3}

Step-by-step explanation:

Assuming that the first exponent in the formula for the curve should be 3, not 2...

y=x^3-2x^2-4x+1

The derivative is

y'=3x^2-4x+4

The slope of the tangent line at the point (-1, 2) is the value of the derivative at x = -1.

y'|_{x=-1} = 3(-1)^2-4(-1)+4=3-4+4=3

The slope of the normal line is the opposite reciprocal of the slope of the tangent line.

m_{\text{normal} = -\frac{1}{3}

Using the Point-Slope form of a linear equation, the normal line is

y-2=-\frac{1}{3}(x-(-1))\\y-2=-\frac{1}{3}(x+1)\\y=-\frac{1}{3}x-\frac{1}{3}+2\\y=-\frac{1}{3}x+\frac{5}{3}

5 0
3 years ago
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