The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
m = 200 miles
Step-by-step explanation:
Rental Co. A: A(m) = $35 + ($0.10/mile)(m), where m is the number of miles driven
Rental Co. B: B(m) = $25 + ($0.15/mile)(m)
Set these two dollar amounts equal to each other and solve for m:
$25 + ($0.15/mile)m = $35 + ($0.10/mile)(m). Combine like terms, obtaining:
($0.05/mile)m = $10; then m = ($10) / ($0.05/mile), or 200 miles.
The price charged by the two companies would be the same when the car has been driven 200 miles.
Jose has 3 more shirts than he has pants.
Answer: It's 6.28319 feet
Step-by-step explanation: