The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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Answer:
1. 44 + 3x
2. 2y - 8
3. x - 6
15. 
16. 
17. 
Step-by-step explanation:
1. 7² + 2² - 5 - 4 + 3x
49 + 4 - 5 - 4 + 3x
53 - 5 - 4 + 3x
48 - 4 + 3x
44 + 3x
2. - y - 5 + y + 2(2y-y) - 3
-y - 5 + y + 4y - 2y -3
-y - 5 + 5y - 2y - 3
4y - 2y - 5 - 3
2y - 8
3. 5x -3 - x - 3(x + 1²)
5x - 3 - x - 3x - 3
4x - 3x - 3 -3
x - 3 -3
x - 6
15. 
= 
= 
= 
→
16. 
= 
= 
= 
→ 
→
17. 
= 
= 
= 
→
Hope this helps.
ANSWER
========
Ratio of 8th graders to 7th graders = 3 : 2
Let the number of graders be 3x and 2x
Number of 8th graders = 18
So , 3x = 18
x = 18/3 = 6
Number of 7th graders = 2 × 6 = 12
Ratio of 6th graders to 7th graders = 5 : 4
Let the number of graders be 5a and 4a
Number of 7th graders = 12
So , 4a = 12
a = 12/4 = 3
Number of 6th graders = 5×3 = 15 ANS
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#BE BRAINLY
The given histogram represents <span>the number of hamburgers students ate in a month :
</span>
From the histogram we can conclude the following:
(1) 8 students ate (0 - 4) hamburgers
(2) 3 students ate (5 - 9) <span>hamburgers </span>
(3) 2 students ate (10 - 14) <span>hamburgers
</span>
note: we don't know how many students ate exactly 5 hamburgers.
<span>So, the answer
</span>
The information which is provided in the histogram<span>
</span><span>
</span><span>The number of students who ate 10 hamburgers or more
</span>
