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3 years ago

11

PLEASE HELP ASAP!!! 10 points!!!!

2 answers:

creativ13 [48]3 years ago

8 0

Answer: y=-1/2x+2/3

Hope this helps! attached the image

Tanya [424]3 years ago

8 0

90 which is the corcumince of 20

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If m1=2x° and m3=3x° what is m1

olga_2 [115]

Answer:

36

Step-by-step explanation:

Using the angle addition postulate

angle 1+angle 2+angle 3=180

Angle 2 is 90 degrees,

Angle 1 is 2x degrees

Angle 3 is 3x degrees

Plug this into equation

$2x + 90 + 3x = 180$

$5x + 90 = 180$

$5x = 90$

$x = 18$

Plug 18 into 2x

$2(18) = 36$

5 0

2 years ago

The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000

Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

$P = P_0 \times e^{rt}$

where P is the population after time t, $P_0$ is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

$2 P_0 = P_0 \times e^{r 1/3}$

$2 = e^{r \; 1/3}$

$ln 2 = r \; 1/3$

$ln 2 \times 3 = r$

$2.08 \% = r$

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

$90000 = P_0 \times e^{2.08 \; 5/3}$

$\frac{9000}{e^{2.08 \; 5/3}} = P_0$

$2810 = P_0$

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

$P = 2810 \times e^{2.08 \; 5}$

$P = 92335548$

3 0

3 years ago

I Need Help!!<br><br><br> Identify each congruence transformation that maps ABC to DEF

timama [110]

Answer:

A and F

Step-by-step explanation:

Option A works as a transformating, and option a is the same as potion f

6 0

3 years ago

y = 2x squared + 5x -3 can be written in the form y= 2( x+a) squared + b . Find the value of a and the value of b.

Elan Coil [88]

General vertex form:

$y = m(x − a)² + b \: with \: vertex \: at \: (a, b)$

Given :

$y = 2x² + 5x - 3$

Extract "spread factor" m

$y = 2( x² + \frac{5}{2} x) - 3$

Complete the square

$y = 2(x² + \frac{5}{2}x + ( \frac{5}{4})²) - 3$

$- 2( \frac{5}{4})²$

Write as a squared binomial and simplify the constant

$y = 2(x + \frac{5}{4})² - 6 \frac{1}{8}$

Re-write to match signs of standard general form:

$y = 2(x - ( - \frac{5}{4}))² \: + ( - 6 \frac{1}{8})$

3 0

2 years ago

find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on

enyata [817]

Let $f(x)=\tan^{-1}x$ . Then $f'(x)=\frac1{1+x^2}$ . Note that $f(0)=0$ .

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n$

This means that for $|-x^2|=|x|^2$ , or $-1$ , we have

$\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}$

Integrate the series to get

$f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

$\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

6 0

3 years ago