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3 years ago

Solve for final product and show work for Na + NO3 ?

Chemistry

1 answer:

kirza4 [7]3 years ago

3 0

Sodium (Na) is atomic number 11, so it has 1 valency

While Nitrate (NO₃) has valency 1

Sodium has an extra electron while nitrate needs an extra electron, sodium gives its electron to nitrate and forms a bond,

NaNO₃ (Sodium nitrate)

Happy to help :)

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One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867

Thepotemich [5.8K]

Answer:

(A)

Density = Mass / Volume

Mass = Density × Volume

$= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene$

$1C_6 H_5 CH_3 + 9 O_2 > 7 CO_2 + 4 H_2 O$

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of $CO_2$ gas and 4 moles of $H_2 O$ Vapour

So the mole ratio is 1 : 11

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $$

(C)

1mole contains $6.022\times10^{23}$ molecules

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $$

6 0

3 years ago

In your own words, explain how multiple approaches to a scientific investigation can be used to obtain the same result. Provide

aleksandr82 [10.1K]

Answer:B

Explanation:

5 0

2 years ago

For questions #8 – 9 use the following pictures:

Annette [7]

8. The picture that would best represent atoms in the gas of a neon sign is the image B. This is because they have room for movement in that their distance between each particle is great. That is why gases has greater volume compared to liquids and solids.

9. The picture that would best represent a rock is the image C. The solid molecules are so pact that they have no room for movement.

6 0

3 years ago

Which equation is most likely used to determine the acceleration from velocity vs. time graph?

SVEN [57.7K]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Acceleration.

a = V2-V1/t

so the correct answer is, a = ∆v/t

option C.) is correct, a = ∆v/t

5 0

2 years ago

Read 2 more answers

How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°

kotykmax [81]

Answer:

$\boxed {\boxed {\sf 1076.196 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

$q=mc\Delta T$

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

The change in temperature is the difference between the initial temperature to the final temperature.
The temperature changes from 23.0°C to 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
ΔT= final temperature - initial temperature
ΔT= 67°C - 23°C
ΔT= 44°C

Now we know all the values.

m= 26.3 g
c= 0.930 J/g °C
ΔT= 44°C

Substitute the values into the formula.

$q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)$

Multiply the first two numbers together. The units of grams cancel.

$q= 24.459 \ J/ \textdegree C \times 44 \textdegree C$

Multiply again. This time, the units of degrees Celsius cancel.

$q=1076.196 \ J$

1076.196 Joules of heat will be absorbed by the piece of aluminum.

4 0

2 years ago