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Juliette [100K]
3 years ago
9

A 1.5L intraveneous (IV) solution contains 919 grams glucose (C6H12O6). What is the molarity of this solution?

Chemistry
1 answer:
AleksandrR [38]3 years ago
3 0

Answer:

3.4 M

Explanation:

M = grams/molar mass = ans./volume(L)

M = 919/180 = ans./1.5

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Which is a restriction on both workers and producers that keeps the labor market from being a completely free market?
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Balanced chemical equations only show formulae, not names. A balancing number, written in normal script, multiplies all the atoms in the substance next to it.

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what the type of solid materials are typically hard, have high melting pionts and poor electrical conductivities​
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Ionic solids

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Which type of rock forms when an existing rock changes under extreme pressure and intense heat?
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Use the pictures sent<br> Please help
Digiron [165]

Answer:

C(i) the elements are lead (Pb), nitrogen (N) oxygen (O). Lead is found as the Pb 2+ ion and nitrogen and oxygen form the nitrate ion NO 3 –. Its chemical formula is Pb (NO 3) 2.

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I hope this helped

6 0
2 years ago
Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of disappearance of Cl2
s2008m [1.1K]

Answer : The rate of formation of NOCl is, 8.48\times 10^{-2}M/s

Explanation : Given,

Rate of disappearance of Cl_2 = 4.24\times 10^{-2}M/s

The given rate of reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl

The expression for rate of reaction :

\text{Rate of disappearance}=-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[Cl_2]}{dt}

\text{Rate of formation}=\frac{1}{2}\frac{d[NOCl]}{dt}

From this we conclude that,

\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}

\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}

\frac{d[NOCl]}{dt}=2\times \frac{d[Cl_2]}{dt}

Now put the value of rate of disappearance of Cl_2, we get:

\frac{d[NOCl]}{dt}=2\times (4.24\times 10^{-2}M/s)=8.48\times 10^{-2}M/s

Therefore, the rate of formation of NOCl is, 8.48\times 10^{-2}M/s

7 0
3 years ago
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