Kp= (COCl2)/[(CO)(Cl2)]= 1.49 x 10^8
1.49 x 10^8= (COCl2/((2.22x10-4)(2.22x10-4))
COCl2= 1.49x10^8 x ((2.22x10-4)(2.22x10-4))= 7.34 atm
Answer:
chemical energy, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic.
Since we are told that 1L of air contains 0.21L of oxygen, you can use the conversion (0.21L O₂)/(1L air). That means that you can just multiply 6.0L by 0.21L to get 1.26L of O₂.
that means that the lungs can hold about 1.26L of oxygen.
I hope this helps. Let me know if anything is unclear.
Copper. thats the way copper oxidized. like the statue of liberty
Answer:
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Explanation:
As given
60 min = 50 gm (1)
then we know half-life mean half amount decay time
so we can write as the half of 200 is 100 gm hence
T 1/2 = 100 (2)
solving these two equation by cross multiplication we will get
T 1/2 = 120 min
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