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11 months ago

The bronsted-lowry definition views an acid-base reaction as a _____ transfer reaction.

Chemistry

1 answer:

Effectus [21]11 months ago

7 0

The bronsted-lowry definition views an acid-base reaction as a proton transfer reaction.

Johannes Nicolaus Brnsted and Thomas Martin Lowry independently developed the Brnsted-Lowry theory, also known as the proton theory , which states that any compound that can transfer a proton to another compound is an acid, and the compound that accepts the proton is a base.

A proton is a nuclear particle with a unit positive electrical charge; it is denoted by the symbol H+. Similar to how a substance can only act as a base when a acid is present, a substance can only act as an acid when a base is present. Additionally, an acidic material transforms into a basic when it loses a proton.

In addition, when a basic substance obtains a proton, it generates an acid known as the conjugate acid of a base, and when an acidic substance loses a proton, it forms a base known as the conjugate base of an acid.

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Carbon-14 has a half-life of approximately 5700 years. How much of a 1000g sample will be left undecayed and still radioactive a

Artist 52 [7]

Answer:

option C is correct (250 g)

Explanation:

Given data:

Half life of carbon-14 = 5700 years

Total amount of sample = 1000 g

Sample left after 11,400 years = ?

Solution:

First of all we will calculate the number of half lives passes during 11,400 years.

Number of half lives = time elapsed/ half life

Number of half lives = 11,400 years/5700 years

Number of half lives = 2

Now we will calculate the amount left.

At time zero = 1000 g

At first half life = 1000 g/2 = 500 g

At second half life = 500 g/2 = 250 g

Thus, option C is correct.

4 0

2 years ago

What will you observe when you open a bottle of concentrated hydrochloric acid?

Soloha48 [4]

Answer:

Strong affinity of HCl gas for moisture in air results in forming of droplets of liquid solution which appears like a cloudy smoke.

Explanation:

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7 0

2 years ago

calculate the quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis

abruzzese [7]

The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.

Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.

Calculation :-

using the titration equation,

M₁V₁ = M₂V₂

substituting values

V₁ = M₂ V₂/M₁

= 0.2 × 10 ml /0.01

= 2/0.01 ml

= 200 ml.

A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.

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<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.

5 0

1 year ago

4Fe +302 + 2Fe2O3 <br> How many grams of Fe2O3 will be produced from 10.0 g of Fe and 7.00 g of O2?

Molodets [167]

Answer:10g of Fe produces 14.37g of Fe2O3

7g of O2 produce 46.84g of Fe2O3

Explanation:

3 0

2 years ago

How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?

Ksenya-84 [330]

Answer:

a. Approximately $1.3\; \rm mL$ .

b. Approximately $7.2\; \rm mL$ .

Explanation:

The unit of concentration " $\rm M$ " is equivalent to " $\rm mol \cdot L^{-1}$ ", which means "moles per liter."

However, the volume of both solutions were given in mililiters $\rm mL$ . Convert these volumes to liters:

$\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L$ .

$\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L$ .

In a solution of volume $V$ where the concentration of a solute is $c$ , there would be $c \cdot V$ (moles of) formula units of this solute.

Calculate the number of moles of $\rm NaCl$ formula units in each of the two solutions:

Solution in a.:

$n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol$ .

Solution in b.:

$n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol$ .

What volume of that $3.4\; \rm M$ (same as $3.4 \; \rm mol \cdot L^{-1}$ ) $\rm NaCl$ solution would contain that many

For the solution in a.:

$\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL$ .

Similarly, for the solution in b.:

$\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL$ .

8 0

2 years ago