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Licemer1 [7]
3 years ago
5

Please help w/ this question image attached

Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

Since each leg of the large trapezoid is bisected, then HJ is the average of the lengths of KL and NM.

HJ = (KL + NM)/2

2(HJ) = KL + nm

2(5x + 2) = 4x + 1 + 27

10x + 4 = 4x + 28

6x = 24

x = 4

KL = 4x + 1 = 4(4) + 1 = 16 + 1 = 17

Answer: KL = 17

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An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0
3 years ago
Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d
Olegator [25]

Answer:

The speed of the cars is 32 \frac{km}{h}

Step-by-step explanation:

First we must first have the clear concept that speed=\frac{distance}{time} or s=\frac{d}{t}

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: s_{1}=s+1 , t_{1}=2 and d_{1}= d_{2}

Car 1: s_{2}=s-10 , t_{2}=3 and d_{1}= d_{2}

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

d_{1}=s_{1}*t_{1}

d_{1}=(s+1)*2

d_{1}=2s+2

<em>Car 2</em>

d_{2}=s_{2}*t_{2}

d_{2}=(s-10)*3

d_{2}=3s.30

d_{1}=d_{2}

2s+2=3s-30

2+30=3s-2s

32=s

The speed of the cars is 32 km/hr

7 0
3 years ago
Lydia bought 2 ½ gallons of paint and used 1 ½ gallons of paint. What fraction of the paint did she use?
grandymaker [24]
3/5 is used

2 1/2 gallons can be expressed as 5/2
1 1/2 gallons is the same as 3/2the fraction used is amount used over total amount

So (3/2)/(5/2) the 2 s cancel leaving you with 3/5
6 0
3 years ago
Complete the multiplication problem to find the answer.
melisa1 [442]

Answer: 88.74

Step-by-step explanation:

3 0
3 years ago
HEY YOU! YES YOU, HOTTIE PLS HELP ME &lt;3
Setler79 [48]

Answer:

None of the above if there is that answer because one is 4 times and the other is 4 to the x power which is exponential

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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