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2 years ago

Chromium has the electron configuration 4s1 3d5 beyond Argon. What are the L and S values?

Physics

1 answer:

Marizza181 [45]2 years ago

6 0

Answer: Chromium

Why Chromium has [Ar] 3d5 4s1 and Copper has [Ar] 3d10 4s1? Socratic.

Explanation:

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What property is a characteristic of a pure substance that can be observed with out changing the substance into something else

WARRIOR [948]

physical property is a characteristics of a pure substance that can be observed without changing the substance into someone else.

4 0

2 years ago

A certain lightning bolt moves 10.0 C of charge. How many charges have been moved if the fundamental unit of charge is 1.6 x 10-

Andrej [43]

To solve this problem, use the ratio given by the total number of electrons or protons that exist as a function of the total charge, and inversely proportional to the value of the fundamental charge. The number of fundamental unit $|q_e|$ that constitutes a charge of 40.0C can be calculated as

$N = \frac{|Q|}{|q_e|}$

Here,

$q_e$ = Value of charge and it is the fundamental charge

Q = Total Charge

N = Total number of electron or protons

The number of fundamental units is calculated as follows

$N = \frac{10.0C}{1.6*10^{-19}C}$

$N = 6.25*10^{19}$

Therefore the number of fundamental charge units moved by lightning bolt is $6.25*10^{19}$

8 0

3 years ago

A cylindrical container with a cross-sectional area of 66.2 cm2 holds a fluid of density 856 kg/m3 . At the bottom of the contai

Ugo [173]

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a) Let us assume the depth be h

As we know that

$Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h$

After solving this,

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

Given that

height of the extra fluid is

$h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}$

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

$Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000$

Pb' = 122 KPa

3 0

3 years ago

An object is placed between two plain mirrors which make angle 45 degree with each other. Distance between all adjacent images a

marysya [2.9K]

I have a formula here that might just help you solve the problem on your own:

The number of images depends on the angle between the two mirrors. The number of images formed in two plane mirrors inclined at an angle A to each other is given by the formula:

Number of images = 360<span>/A - 1.
</span>
I hope my guide has come to your help. God bless and have a nice day ahead!

3 0

2 years ago

what should be done in order to increase the gravitational force between two objects? Decrease the mass of both of the objects.

sesenic [268]

Answer:

Decrease the distance between the two objects.

Explanation:

The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:

F = GM₁M₂ / r²

NOTE: G is the gravitational force constant.

From the equation:

F = GM₁M₂ / r²

We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.

Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.

Considering the question given above,

To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.

8 0

2 years ago