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3 years ago

Chromium has the electron configuration 4s1 3d5 beyond Argon. What are the L and S values?

Physics

1 answer:

Marizza181 [45]3 years ago

6 0

Answer: Chromium

Why Chromium has [Ar] 3d5 4s1 and Copper has [Ar] 3d10 4s1? Socratic.

Explanation:

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A ball is Thrown Upward with An initial velocity of 30 m/s , How high does it rise from the ground when the ball reaches the hig

kobusy [5.1K]

Answer:

The maximum height reached by the ball is 45.92 m

Time taken to fall down to half of its height is 2.2 s

Explanation:

Given;

initial velocity of the ball, u = 30 m/s

final velocity of the ball at the highest point, v = 0

The maximum height reached by the ball is calculated as;

v² = u² - 2gh

where;

h is the maximum height reached by the ball

0 = 30² - (2 x 9.8)h

19.6h = 900

h = 900 / 19.6

h = 45.92 m

Time taken to fall to half of its height is calculated as;

when falling down, the final velocity v becomes the initial velocity = 0.

Apply the following kinematic equation;

h = ut + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

where;

h = 45.92 m is the maximum height reached

half of h = 45.92 / 2 = 22.96 m

22.96 = ¹/₂gt²

$t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 22.96}{9.8} }\\\\t = 2.2 \ s$

3 0

3 years ago

11) Arthur and Betty start walking toward each other when they are 100 m apart. Arthur has a speed of 3.0 m/s and Betty has a sp

sleet_krkn [62]

Answer:

100 m

Explanation:

Arthur and Betty should be walking the same amount of time if they start walking at the same time and stop when they meet = t

Speed of Arthur = 3 m/s

Speed of Betty = 2 m/s

Distance = Speed × time

Distance covered by Arthur = 3t

Distance covered by Betty = 2t

The distance covered by both of them will be 100 m

$3t+2t=100\\\Rightarrow 5t=100\\\Rightarrow t=\frac{100}{5}\\\Rightarrow t=20\ s$

The speed of dog is 5 m/s

Spot is running back and forth at 5 m/s for 20 seconds

In 20 seconds the distance covered by the dog is

$\mathbf{5\times 20}=\mathbf{100\ m}$

5 0

4 years ago

DONT ANSWER IF YOU DONT KNOW. For a person who is farsighted, what would they need to have a correct focal point?

fiasKO [112]

A) Convex Lens.... hope it helps :)

5 0

3 years ago

A sky-diver jumps from a stationary balloon. His initial downwards acceleration is 10m/s².

Tatiana [17]

Explanation:

a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.

5 0

2 years ago

2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after

sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

$A(t)=A_oe^{\frac{-bt}{2m}}$

or amplitude for unforce oscillation

$\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}$

$\frac{6bt}{2m}=1$

$b=\frac{m}{3T}$

Now, provided in the question Amplitude of the driven oscillation

$A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}$

the value of the maximum amplitude is obtained $(k=m\omega_d^2)$

thus,

$A=\frac{F_{max}}{(b\omega_d}$

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

$0.075=\frac{nF}{((\frac{m}{3T})2\pi}$

n = 1810

hence, there were 1810 people on the bridge

b) $A=\frac{F_{max}}{(b\omega_d}$

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

$A=\frac{F_{max}}{(3b\omega_d}$

$A=\frac{1}{(3}A_o$

$A=\frac{1}{(3}0.075$

A = 0.025 m = 25 mm

6 0

3 years ago